Solve for 2cosx - sin2x= cos2x over the interval [0,2pi) 1.) x=pi/6 and 11pi/6 2.) x=5pi/6 and 7pi/6 3.) x=2pi/3 and 4pi/3 4.) x=pi/3 and 5pi/3

Solve for 2cosx - sin2x= cos2x over the interval [0,2pi) 1.) x=pi/6 and 11pi/6 2.) x=5pi/6 and 7pi/6 3.) x=2pi/3 and 4pi/3 4.) x=pi/3 and 5pi/3

law of sines

Solve the triangle using the law of sines: a = 75 b = 100 c = ? <A = 30° <B = ? <C =? My work: Sin B / 100 = sin 30 / 75 Sin B =...

Given: <B = 29 degrees. <C = 51 degrees. b = 44 51 + 29 = 80 degrees. <A = 100 degrees. Sin51° / c = sin29°/44 c = 44sin51° / sin29° c...

I need to know where this angle would go I'm order to solve for the rest of the triangle. A 12.0m tall power pole is leaning 6.5° off of the vertical because of soil erosion...

In ΔPQR, q = 45 cm, ∠Q=117° and ∠R=18°. Find the length of p, to the nearest 10th of a centimeter.

A metal ring with diameter 1.94 metres is suspended in a horizontal plane by four support ropes each 5.40 m long, which are attached to points equidistant around the ring, and joined together at a...

A hot air balloon is flying above Groveburg. To the left side of the balloon, the balloonist measure the angle of depression to the Groveburg soccer fields to be twenty degrees 15’. To the right side...

1) a=52 degrees, b=14,c=6 2)a=5,b=11,c=9

1. A=33 degrees, a=20,b=13 2. C=137degrees, a=19,c=8

I'm having trouble finding the missing sides and angles for the triangle. I know you have to use law of sines to find them, but I'm having trouble. Any help is greatly appreciated! A=...

AD is drawn perpendicular to BC ,m(BAD)=alpha,and m(CAD)=beta Prove that:AD=a*cos(alpha)*cos(beta)/sin(alpha+beta)

Side a = 26; Side b = 20; Angle B = 15 degrees

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Points A and B are in opposite sides of a lunar crater. Point C is 45 meters from point A. The measure if angle BAC is 114 degrees and the measure of angle ACB is 45 degrees. What is the width of...

Law of Sines Written by tutor Carol B. The law of sines is a proportion used to solve for unknown sides and/or angles of any triangle. In any triangle, the ratio of a side length to the sine of its opposite angle is the same for all three sides. Law of sines formula: a/sin A = b/sin B = c/sin C Use the law of sines if (1) one side length and its opposite angle measurement... read more

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