Double integral - calculating area

Calculate the area of the region bounded by the two curves, y = 4 - x2 and y = x + 2.   The answer is meant to be 9/2 but I just cannot get it!!! Maybe my bounds are incorrect......

Definite Integral Evaluation

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volume of this solid

i dont know how to solve this problem : find the volume of the region bounded by x = 1 − y^2 ,x = 2 + y^2, y = −1, y = 1, is revolved about the y-axis ! thank you

Jul 1 | Marcio from West Columbia, SC | 1 Answer | 0 Votes

find the volume of this solid

How do you find the volume of the region bounded by y=x^2-1 , x=2 , y=0 , is revolved about the y-axis? thank you

Jul 1 | Marcio from West Columbia, SC | 1 Answer | 0 Votes

if f(x) is a function and its anti derivative is F(x) then why F(a) - F(b) gives the area under curve of f(x) from a to b. Is there any prove for this.

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Integration of 1 minus cot Square x

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Find where the curve y=x^2-x-1 meets line y=5. Find area of the region bounded by the curve and line y=5      

at a sale on winter clothing, cody bought two pairs of gloves and four hats for $43.00. Tori bought two pairs of gloves and two hats for $30.00.

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Write following rational function in partial fraction form: [2] / [ (x^+1)^2 (x+2) ] Ans: A = -2/25 B = 4/25 C = -10/25 D = 20/25 E = 2/25

using integration find the area of the region bounded by the lines y=2+x ,y=2-x and x=2

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Question: Integrate --> 5 / (10^2 +90)  Ans: 1/6 arctan (t/3) + c    formular: (a^2+x^2) = a^(-1) arctan xa^(-1)

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What is the arclength of r=6sin(3θ)? Given the formula Lpolar= ∫√[r^2+(dr/dθ)^2]dθ I can find the arc length using the r stated above and r'=18cos(3θ) Given that one petal is...

Find integration of (1+x^4)/(1-x^4)^3/2

This question is on integration pls solve this 

Question about integration

Integration of 1/x(x4 -1)  

Integrate -(5x-3)dx

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∫dx/(x+1) - ∫dx/(x+2) = log| (x+1)c/(x+2) |

Feb 12 | Kersh from New York, NY | 2 Answers | 0 Votes