Explain why the total area of a region is 25/3 units, but the value of the integral for the same interval is 16/3 units.

Explain why the total area of a region is 25/3 units, but the value of the integral for the same interval is 16/3 units.

Evaluate the integral of dt/t√t from 1 to 4

The equation of a curve is y=x4+4x+9. (i.) Find the coordinates of the stationary point on the curve and determine its nature. (ii.) Find the area of the region enclosed...

Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = Ln(x), y = 1, and x = 1 is revolved around the line y = −1

Take the above function. If x=1, the velocity is 0 and position is -22. FInd v(t) at any time. Find x(t) at any time. I have no clue how to answer this. Absolutely no...

find the volume generated by revolving the region between them about the x-axis: f(x)=2 and g(x)=cos(x) [0,Pi/2]

Use the Shell Method to compute the volume of the solids obtained by rotating the region enclosed by the graphs of the functions y=x^2, y=8−x^2 and to the right of x=1 about the y-axis.

I just need to see how the integral would be set up. From there I ca solve on my own.

Use the limit definition to evaluate the definite integral fnInt (2x^3+3)dx lower bound-2 upper bound - 6. (Use right endpoints for c sub-i and equal subintervals

Find y(x) ?! For dy/dx= a +b(y)+c/x+e(y/x) a,b,c and e are constants

After taking the integral I have (1/7)tan^7x+C-(1/5)tan^5x-C. I got this by breaking a tan^2x off and converting it into sec^2x-1. My question is what happens to my C when I have C-C?

In integration, it is given as: Integration of 1/(1-x^2)^(1/2) = sin^-1 (x) and Integration of 1/(1-x^2)^(1/2) = - cos^-1 (x) Does this...

∫02 [x]nf'(x) dx Please hep me with this integration. It includes an integral part and a derivative :O

integrate f(t) cos (n*pi*t)/T/2)dt with limit T/2 and 0

I have not been able to sove solve this sum..help me pls

Integration from 0 to π cos6x cos^8x

I'm trying to integrate (x)/(d+L-x) respect to x but I get -(d+L)ln(d+L-x) + d + L -x. The correct answer is -(d+L)ln(d+L-x) -x. What I did was to change the variable...

We have to find the integration of ∫20160 [arctanx]dx the limits are from 0 to 2016 . [.] means greastest integer

siny dx √(cos³xcos(x-y))

Please help me to find the limit here. Answers will be appreciated. Thanks in advance

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