Translate ΔABC by vector AB to form straight <ABB' along the vector. The isometric properties of translation preserve _________, thus m<1 = m<B'BC'. Since...

Translate ΔABC by vector AB to form straight <ABB' along the vector. The isometric properties of translation preserve _________, thus m<1 = m<B'BC'. Since...

The proof is a 6 point questions

is it true or false that if two different lines are parallel to a third line, the two lines are not parallel to each other?

Segment AB is congruent to segment AB. What propert does this statement shows?

Given: triangle SVX is congruent to triangle UTX and Line SV is || to line TU Prove: VUTS is a parallelogram Image: It's a parallelogram, with one line going from corner...

The vertex is angle A

Image 33k

Let ABC be an isosceles triangle with AB = AC. Suppose that the bisector of angle B meets AC at D and that BC = AD+BD. Determine angle...

Given: Line Segment AB ≅ Line Segment CD, Line Segment BC ≅ Line Segment DA Prove: △ABC ≅ △CDA

Statements 1. O is the midpoint of Line Segment MQ. 2. 3. O is the midpoint of Line Segment NP. 4. 5. <MON ≅ <QOP 6. △MON ≅ △QOP Reasons 1. Given 2...

Statements 1. Line Segment AB ≅ Line Segment CD 2. Line Segment AB || Line Segment CD 3. <ABC ≅ <DCB 4. Line Segment BC ≅ Line Segment CB 5. △ABC ≅ △DCB Reasons 1...

Statements line WXY m<WXY = 180° m<WXZ = 135° m<WXY = m<WXZ + m<ZXY 180° = 135° + m<ZXY 45° = m<ZXY m<ZXY = 45° Reasons Given...

** Will need 3 steps. If m<1 = 40° and m<2 = 50°, then the angles are complementary.

Statements: 9 = 4x - 3(x - 2) 9 = 4x - 3x + 6 9 = x + 6 3 = x x = 3 Reasons: Given ...

Statements: m ⊥ l, n ⊥ l <1 is a right angle <2 is a right angle <1 =~ <2 m || n Reasons: Given ...

Statements: <1 =~ <2 m<1 = m<2 <1 and <2 are a linear pair <1 and <2 are supplementary m<1 + m<2 = 180° m<1 + m<1 = 180° 2 * (m<1)...

Statements: l || m <1 =~ <3 <1 and <2 are supplementary <3 and <2 are supplementary a || b Reasons Given Given ...

Statements BC = 8 line segment BC =~ line segment CD line segment AD =~ line segment CD Reasons Given Transitive...

Statements AB = DE, BC = CD AB + BC + CD =~ AD DE + CD + BC = BE AB + BC + CD = BE AD = BE Reasons Given ...

Statements m<AQB = m<CQD m<AQB + m<BQC = m<AQC m<CQD + m<BQC = m<BQD m<AQB + m<BQC = m<BQD m<AQC = m<BQD Reasons Given...

Could you prove and explain how you did it/ what properties you used. A____L_________S____K <---- Line Segment

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