Just need the first derivative of this function, struggling with there to begin

Just need the first derivative of this function, struggling with there to begin

What is dy/dx for e^(x+y) =y

a) f(x) = 3x3 - 4√x + 1 b) f(x) = 2x (3x2 - x) c) f(x) = (x2 + x - 6) / &nbs...

F (x)=(12x-3)e^x

f(x)=(4x-4)((5x^3)-(x^2)+1)

f(x)= x^x2 I got f'(x)= x^x2 (x+2xlnx) It says the answer is x^x2+1 (1+2lnx) I have no clue how to get to that answer...

I am not sure how to do this. So far I did Cos(x^(1/2)^3 So I did the chain rule to make Cos(u) where u = x^(3/2) Then I got -Sin(sqrtx)^3*(3/2)x^(1/2) Which then simplifies to (-3Sin(sqrtx)(sqrx))/2 What...

y=(4-2x-3x2)5 y'= 5(-3x2 -2x+4)4*(-6x-2) I used a online derivative calculatir to check my answer but it gave something completly different.

derivative of y = e^((k)tan(sqrt(3x)))

derivative of y = [x + (x + sin(x)^2)^3]^7

derivative of y = [x + (x + sin(x)^2)^3]^7

Hi, I tried solving this and got (1)/(2sqrt2) but my book says the answer is (3)/(2sqrt2)

U=2L1/2x C1/2

Suppose that f(2) = −5, g(2) = 3, f '(2) = −2, and g'(2) = 1. Find h'(2) for h(x) = g(x)/(1+f(x))

It says to eliminate one variable so I eliminated x. A=xy L2=x2+y2 x=(L2-y2)1/2 A=y*(L2-y2)1/2 =(L2y2-y4)1/2 Derivative =1/2(L2y2-y4)-1/2...

The derivative of a polynomial is f'(x) = (x-3)^2 (x+7)

the particle is moving along the curve y=sqrtx. As the particle passes through the point(4,2) its x-coordinate increases at a rate of 3cm/s. How fast is the distance from the particle to the...

So far I have: y=-2+5 y1 = (-2(x+h)+5-(2x+5))/h (-2-2h+5-2x-5)/h (-4x-2h)/h If I set h=0 it becomes -4x/0 which...

"Suppose g is the inverse function of a differentiable function f, and G(x)=1/g(x). If f(3)=7 and f'(3)=1/9, find G'(9). FInd G'(7)." Please show all steps- thanks so much...

Find the derivative of f(x) = sqrt(36-x^2) / 9x when x=2

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