Q = No. of quarters = Value 25Q cents N = number of nickels , Value = 5N cents D = No. of dimes Value = 10D cents Given N = 2 Q D = Q -4 500 = 25 Q + 5 N + 10 D = 25Q + 5 (2Q) + 10 ( Q-4) = 25 Q + 10 Q + 10 Q - 40 = 45 Q - 40 Given Q = 540/45...

Q = No. of quarters = Value 25Q cents N = number of nickels , Value = 5N cents D = No. of dimes Value = 10D cents Given N = 2 Q D = Q -4 500 = 25 Q + 5 N + 10 D = 25Q + 5 (2Q) + 10 ( Q-4) = 25 Q + 10 Q + 10 Q - 40 = 45 Q - 40 Given Q = 540/45...

To me it appears that stretching is from 30cm to 50 cm = 20 cm for a work or PE of 7 J so 1/2(K X 2) = 7 = 1/2 ( K * 0.2*0.2) should be used to the value of K = 350 N/m From here we can go to the second part of question

Some thing missing

Question seems to be incomplete

Which thermodynamic process? A) Isobaric expansion B) Isothermal expansion C) Adiabatic expansion (answer)

As Adiabatic curve is steeper than isothermal and Isobaric. The work done in adiabatic process is least as the area between the curve and the volume axis in minimum in such case.

Answer B is correct as it is moving from rarer to denser medium

Physics angular frequency, aplitude (answer)

V = - AwSinwt = -5.3 Sin 21.5 t If X = ACoswt = A Cos 21.5 t where w= Angular velocity 21.5 rad/sec As Aw = -5.3 A = Amplitude =( 5.3 / 21.5 )m X = A at t = 0 X = (5.3/21.5) Cos (21.5*37.7) at 37.7 sec = 0.246 Cos ( 810.55)m Spring PE = 1/2 KX 2 Where...

Physics bullet spring (answer)

Momentum of bullet = mass * velocity = 20* 10 - 3 *259 Momentum of Bullet plus wooden block = Total mass * Combined velocity ( 411 +20) * 10 -3 V Equating the Momentum before and after Find the Value of V Let X = compression of the spring The...

f(x)=3450/(2.5+0.60^x) f '(x) = -3450(ln0.6* 0.6 ^x)) / (2.5 +0.60^x) ^2 = -3450( -0.5108 *0.6^x)/(2.5+0.60^x)^2 Sub x= 8 3450 (0.5108* 0.6 ^ 8)/ (2.5 +0.6 ^ 8) ^2 =3450(0.5198*0.016796)/ (2.5 + 0.016796)^2 =3450*8...

Write the equation in slope-intercept form of the line that has a slope of -7 and y-intercept 6. (answer)

Hi Mckenzie The equation of a line is y = mx +c where m = slope and c= y- intercept So the equation in this case is y = -7x +6

How many green marbles are there? (answer)

Hi Let G = Number of green marbles and R= Number of red marbles G + R = 83 or G = 83 - R G = 4R -7 Substituting 83 - R = 4R -7 83 +7 =5R R = 90/5 = 18 and G = 83 - 18 = 65 Number of green = 65

Let F be the force on each leg of tripod The 3F Cos theta = 111g = 111*9.8 N ( the total weight on the tripod) Here theta = 45 degree 3F *Cos 45 = 111*9.8 F= (111*9.8 * sqrt 2)/3 N

Hi Madison Any audio system which is battery operated has chemical energy stored in its battery. When we switch on this audio device ( example mobile phone) the chemical energy of battery gets changed into electric energy to power the device ( mobile). Then mobile rings...

Trigonometry (answer)

Assuming the two starting at the same time from the same point ( Origin) First one has coordinates as (20,-24) Each one in Km and the second one has position as ( 32, -7) Now find the distance between two points = Sqrt( ( X1-X2)2 +( Y1 -y2) 2 )

Hi Mabia If V = speed for first part speed = Distance1 /time V = Distance1 /2 Second speed = V -15 and time taken = 3 hours Distance 2= (V-15)/ 3 Given Distance 1 + Distance2 = 275 So 2V + (V-15)/3 =275 2V +V/3 = = 275 +5 = 280 7V/3...

Hi jade Average speed = total distance / time taken Total distance = 8 miles time taken = 13 minutes = 13/60 hours = Average speed = 8*60/13 miles per hour =36.92 miles per hour (or approx. 37miles /hr)

Let X and Y be the numbers 2X -Y = 6 and X + 4Y = 39 Solve for X and Y X = 7 and Y = 8

The first plan Let X = number of minutes used The payable amount = 0.25 * X ( in $) In Plan second Payable amount = 34.95 + X*0.12 For the two to be equal X = 268.11 So cost for 269 calls in first plan = $ 67.25 and second plan = $ 67...

Given Y= 24 when X = 13 and Y = 87 when X = 6 Let the equation be Y = mX + C 24 = m*13 +C and 87 = m* 6 +C Give m = -9 and C = 141 Equation of st line is Y= -9X + 141

How about the temperature ? If the temperature is kept as constant then for ideal gas P1V1 = P2V2 21*16 = 4.1*V2 So V2 can be found V2 = 21*16 / 4.1 L If temperature is not constant then P1v1/T1 = P2V2/T2 , We need the values to T1 and T2 to find V2