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Answers by Dr Gulshan S.

Word Problem (answer)

Let R1 = rate of flow of water from pipe 1 ( Volume flowing per hour) and V = volume of tank  R1 = V/t1 = V /4 For pipe 2 R2 =  V/ 6   T = time when both pipes are used  T = V / (R1 + R2) T = V/ ( V/4 + V/6 ) Time taken = 2.4 hrs...

6x(2y-3) -(2y-3) =12xy-18x -2y+3  =6x(2y -3) - 1* (2y-3) Taking (2y-3) as common   it is = (6x-1)(2y-3)

word problem (answer)

Power is given by y =80 e -0.00125  Y becomes 50 watts  So 50 = 80 e -0.00125 80/50 = e 0.00125  8/5 = 1.6 = e 0.00125 ln 1.6 = 0.00125 *t t =ln1.6/0.00125 = 376 days