3x^2+4y^2-36x+24y+132=0

3x^2+4y^2-36x+24y+132=0

Side a = 26; Side b = 20; Angle B = 15 degrees

I figured this out using my calculator but I need help solving through it without. (cosX)/(1+sinX)+tanX

tanU-1/tanU+1=1-cotU/1+cotU

csc^2V-cosVsecV=cot^2V

(tanV+1)^2(tanV-1)^2=2sec^2V

tanU(cscU-sinU)=cosU

(tanv+1)^2(tanv-1)^2=2sec^2v

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