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Answers by Philip P.

Help trig!!! (answer)

Law of Cosines:   a2 = b2 + c2 - 2bc*cos(A)   a2 = (10.25)2 + (5.5)2 - 2(10.25)(5.5)cos(15.6o) = _______   Use you calculator to compute the value of a2.  Once you have a2, take the square root to get a.

Question below (answer)

The equation of a line is:         y= mx + b   where y is the volume of water in the tank at time x x is the time since the tap was opened and the tank started draining m is the slope of the line (rate at which the water is running...

what is cos x? (answer)

1 + tan2x = sec2x   Now sec = 1/cos, so we can rewrite the above equation as:   1 + tan2x = 1/cos2 x   1 + (15/8)2 = 1/cos2x   Solve for cos x

Just plug n=1, n=2, n=3, and n=4 into the equation and see what you get:   n      n(5n-5) = an ------------------------------------------ 1      1(5*1-6) = 1(5-6)=1*(-1) = -1 2      2(5*2-6)...

Pre Calculus (answer)

Vector u has a slope of  (3-0)/(-1-0) = -3.  Vector v has a slope of (1-0)/(3-0) = 1/3.  Since the slopes are negative reciprocals of another, the vectors are perpendicular.  So the answer is c) 90o   To verify, take the dot product of u and v.  If the dot product...

Use the Law of Cosines to find the length of side a:        a2 = b2 + c2 - 2bc cos(A)          where b = 4, c = 8, A = 46o   Once you have the length of side a, use the Law of Sines to find angles B and...

h(t) = A cos(ωt+ø)+h0 h(t) = height at time t A = amplitude = (1/2)*(11 ft) = 5.5 ft ω = angular frequency = 2*pi*(15 revolutions per minute) = 30*pi radians per minute t = minutes ø = phase shift = 0o h0 = height of midline above water = 5.5 ft...

word problem (answer)

Let x = the number of boats in the marina: Three quarters of the boats in the marina are white: (3/4)x 4/7 of the remaining boats (1/4) are blue: (4/7)*(1/4) = (1/7)x The rest are red   The white and blue boats accounts for (3/4)x + (1/7)x = (21/28)x + (4/28)x...