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Answers by Michael F.

1/|×-4|<1/|×+7| multiply both sides by |×-4|×|×+7| to get   |×+7|<|×-4| which says that the points you are looking for are those whose distance from -7 is less than their distance from 4. The middle of that interval is the point -3/2. The points we want...

(m-n)2=m2-2mn+n2=140-2(49)=140-98=42 You only asked for m-n. The question title asks for more.

solve the system (answer)

y=-x+7 y=(x-3)2/2=(x2-6x+9)/2 So -x+7=(x2-6x+9)/2 or -2x+14=x2-6x+9 or 0=x2-4x-5 competing the square we have (x-2)2-9=0 or x-2=±3 or x=5, or x=-1 In which cases y=2 or y= 8 (5,2) and (-1,8) are the solutions

x and y are two numbers each greater than 3, the highest common factor of x and y is 3, the lowest common multiple of x and y is 36, find x and y xy = product of greatest common divisor and least common multiple=3×36=108 Since GCD is 3 we may write x=3a, y=3b since...