"Modifiers" are parts of a sentence that describe a noun or verb, but when they're misplaced, it's not clear what they're supposed to modify. Here's an example that may help. The kid was painting a bird wearing sunglasses. In...
"Modifiers" are parts of a sentence that describe a noun or verb, but when they're misplaced, it's not clear what they're supposed to modify. Here's an example that may help. The kid was painting a bird wearing sunglasses. In...
This is the expression I think you're looking for, right? (4-x)/[2(4-x) +5] So if you're looking for what the expression equals when x=2, all we have to do is plug in the value of x and then follow our order of operations! (4-2)/[2(4-2) +5] The...
Car - Hmm... we can't simplify this fraction at all, because there are no common factors to 77 and 8. However, we can turn this improper fraction into a mixed number. When I think of my 8s times tables, I know that 72 is 8*9, so there...
Marla - So the ratio we're looking for is going to be (chocolate milk)/(all milk), simplified. Let's look at our steps for how we would fill in each of these blanks! Hey, look! We already know how many total cartons of milk there are! It's right in the question! Now...
Hello there, "Biz!" It looks like for this question we are just adding two fractions together. Luckily, they have the same denominator (bottom number)! That makes it a lot easier. 3 2/7 1 4/7 Because we have whole numbers, too, let's add those together...
There are two ways that we can solve this problem! The first is to treat the proportions like fractions (which they are) and try to convert one of the fractions so that it has the same value, but has the same denominator as the other fraction. Luckily, 12 fits perfectly 5 times into 60! 25/60...
Melanie - I can certainly help you with this! Using the substitution method means putting one equation into the other. For example, here, we can put the first equation into the second, because we can substitute for x. x = 6 + 4y -3(x + y) = -36 -3(6+4y +y)...
Hm, ok. Here's how best to tackle this question - let's look at OPTIONS! We have three spots to fill, spots A, B, & C. For spot A, there are 7 different options for what location will fill that spot. Regardless of which location is selected,...
Kevin - Eric has the start to it right, but I'm going to take it one step further for you. When you have two equations and two variables, you can isolate one of the variables (rearrange the equation into x= or y= form) and insert that into the other equation. Here's...
Kieshara - This problem needs to be taken in two steps. First, let's look at the information we have about sweatshirts. 440 total items 4/5 (80%) sweatshirts Next, we can use that information to find out how many sweatshirts were sold,...
Dan - If you're trying to isolate x, the easiest way is to not distribute a in the first equation. This is how I would do it. Original equation: a(x + b) = c Divide both sides by a: [a(x + b)]/a = c/a Cancel out a: [a(x + b)]/a = c/a Simplify:...
Rebecca - The first step is going to be creating a system of equations that represents the word problem. x=regular hours worked y=overtime hours coefficients represent her hourly pay for those hours 6x + 9y = 174 Seeing...
Sydney - I can help you if you give me one or two of the problems that are confusing you! Amanda
Hi Fanny! When working with word problems, the best thing to do is start off by turning the words into math equations. Jose rents 2 movies and 3 games for a total of $15.50. 2m + 3g = 15.5 Meg rents 3 movies and 1 game for a total of $12...
L - Let's look at these one by one. My favorite way to test whether or not how I factored something is correct is by plugging in a value for my variable (a, x, Θ, etc.) and see if my factored expression matches the original one. For #1, let's try that with a=3. Original...
Brittni - Seeing as this prompt relies on the readings used in your class, it's going to be difficult to help you without additional guidance - what specifically confuses you? Having targeted questions will help you get the answers than can guide you to understanding this topic...
Basically, we have two variables, the charge per day and the charge per miles. If we just had your fee or Tom's fee, we wouldn't be able to work it out. We need to use both formulas to help us find the answer. My fee: 3d + 300m = 105 Tom's fee: 5d + 600m = 195 Next we are going...
Harry - If two things multiplied together equal zero, the one of them HAS to equal zero. It helps me to think about it with normal integers at first. If I multiply 2 times any other integer (1, 2, 3, 4, etc.), then I can never get zero. Even if I use negative integers (-1, -2,...
Harry - I see that you posted this question several times with different functions. To get the most out of tutoring or a site like this, don't just rely on people in the forums to answer the questions for you. Ask once, read the response carefully, and try to apply it to the rest...
The key to this is taking complex fractions (whole number plus a simple fraction) and turning them into simple fractions. Original complex fraction: 2 1/2 Add the product of the denominator and whole number to the numerator: 2x2+1=5 This becomes your new numerator: 5/2 You...