The weight W that a horizontal bean can support varies inversely as the length L of the beam. Suppose an 8-m beam can support 1200 kg. How many kilograms can a 14-m beam support?
I would recommend setting this up as a proportion.
8-m / 1200kg = 14-m / x
If you cross...
An office equipment store buys highlighter pens boxes at a wholesale price of $23 each. It then marks up the price by 82%, and sells the highlighter pens boxes. What is the amount of the markup? What is the selling price?
If you markup the highlighter pens boxes from $23 by 82%, you...
Basically you are looking at subtraction of mixed numbers in this problem.
This month the mixed number was 15 3/10cm, last month it was 13 9/10cm.
You would subtract 15 3/10 - 13 9/10 to solve.
It is challenging to do as mixed number, so it is easier...
Can you please ensure that you have the numbers for the first set correct?
The second set, you can solve by substitution:
x + 2y = -7
2x - 3y = 0
Solve for x in first equation:
x = -2y -7
Plug in to second equation:
First you need to find out what the consecutive integers are for the lowest sum 80. The equation should be written below to represent three consecutive integers, whose sum = 80.
X + (x+1) + (x+2) = 80
X + x + 1 + x + 2 = 80
3x + 3 = 80
Johnny’s Car Rental = $2000 Per Day
Car Rental Exclusive = $1000 + $20k (k is for kilometers)
The inequality set up would be: $2000 < $1000 + $20k
You then want to solve for k.
$2000 < $1000 + $20k
-$1000 < -$1000
$1000 < $20k
$1000/$20 < $20k/$20
The Pythagorean Theorem is used when dealing with right triangles. It is used when determining the length of one side of a right triangle. In words it says that in any right angled triangle (one angle being 90°), the square of the hypotenuse is equal to the sum of the squares of both legs.
I would personally disagree with the above answer. The questions is stating that we ARE to assume that the sample is large enough, random and representative. The whole point of taking a sample is that if it is randomly selected and representative of the whole population, the results...
This is how I particularly like to solve these problems.
5x + y =6
5x + 3y = -4
I would first solve for one of the variables either x or y. In this case I’m going to choose y.
5x + y =6
Then you plug that in for the second equation.
5x + 3 (6-5x)...