First divide by 5, and you get 27 27 is then divisible by 3*3*3 or 33 so the prime factors of 135 are 3,5 the prime factorization of 135 is 33 * 5

First divide by 5, and you get 27 27 is then divisible by 3*3*3 or 33 so the prime factors of 135 are 3,5 the prime factorization of 135 is 33 * 5

For the company to break even per month, how many students would have to purchase the course (answer)

REVENUE = $80(S) where S = # OF STUDENTS Fixed costs 2,200 340 5,200 4,000 ------ $11,740 Variable costs = 3(S) to break even, REVENUE - COSTS = 0 So ...

Domain are just the X values. So plug in the 4 X values to get g(x) Domain = {2,4,6,8} x g(x) 2 2 - 13 = -11 4 4 - 13 = -9 6 6 - 13 = -7 8 8 - 13 = -5 so...

just subtract off 0.95 x original value. Or $81 - 0.95*81 = $4.05 This is the same as multiplying $81 x 0.05 = $4.05

C(x) should be vertically dilated by a factor of 3. It doesn't what C(X) is, if linear or a quadratic, etc. Vertically it is just multiplied by 3 since it is zero at time = 0

One pull weighs about 0.011 ounces. How many pulls could be made from 6 pounds of horsehair? (answer)

There are 16 ounces per pound. So 6 pounds = 6 x 16 = 96 ounces divide 96 ounces by 0.011 for the number of "pulls" number of pulls = 96/0.011 = 8727.27 or rounded to an integer, 8727.

S = short piece L = long piece L = 2S S + L = 9 Subst L = 2S S + 2S = 9 3S = 9 S = 9/3 = 3 feet L = 2S = 2(3) = 6 feet

OK, I ASSUME YOU MEAN 4 / (SQRT(2) + 3) CORRECT ?? IF SO, TO RATIONALIZE WE NEED TO REMOVE THE SQRT FROM THE DENOM. WE DO THAT BY MULTIPLYING NUMBERATOR AND DENOMINATOR BY THE CONJUGATE THE CONJUGATE IS USING...

CIRCUMFERENCE = 2*PI*R WHERE R=RADIUS SO 188 = 2*PI*R R = 188/(2*PI) = 29.921 METERS (TO 3 DECIMALS)

Problem with ratios, please help (answer)

let X = NUMBER OF EGG SANDWICHES let Y = NUMBER OF TUNA SANDWICHES SO THE RATIO X/Y = 2/3 NOW, X / (Y + 15) = 1/3 SO WE HAVE 2 EQUATIONS, 2 UNKNOWNS. CROSS MULTIPLY...

1/2 DIVIDED BY 3, OR 1/2 x 1/3 = 1/6 pound each to check: 1/6 + 1/6 + 1/6 = 3/6 or 1/2 pound

MEDIAN - SAME NUMBER OF VALUES LESS THAN AND GREATER THAN EX: 1, 2, 3, 4, 7, 9, 10, 13, 14 7 IS THE MEDIAN BECAUSE THERE ARE 4 VALUES BELOW, AND 4 VALUES ABOVE.

DIST = 90 MI MILES PER GAL = 25 SO TO COMPUTE HOW MANY GALLONS, DIV 90 MI/25 MPG = 3.6 (THAT IS, 25 MI GOES INTO 90, 3.6 TIMES) 3.6 GAL X $2.50 DOLLARS/GAL = $9.00

Check for extraneous solutions (answer)

if I read this right, and the square root is of the quantity (2x+5) SQRT(2X+5) = X + 3 square both sides 2X + 5 = (X+3)^2 2X + 5 = X2 + 6X + 9 combine terms, and put all on...

Interest = 2.65% Initial Value = $10,000 after 1 year, the value is 10,000 x 1.0265 = 10,265.00 after 2 years, the value is 10,000 x 1.0265 x 1.0265 so each year the previous value is just mult by 1.0265 i year ...

Assuming the 324 square feet of fabric is square in shape, each side would be 18 feet (18 x 18 = 324) an inscribed circle on this square would have a diameter of 18, or a radius of 9 feet.

mean = 82 1 std dev = 5 2 std dev = 10 for a normal distribution +/- 1 std dev = 68.2 % or 34.1% to each side of the mean +/- 2 std dev = 95.4 % or 47.7% to each side of the mean I hope this graphically shows the...

I will assume you know how to do synthetic division for testing factors If not long division should also work For synthetic division we write the coeff of the polynomial, then use the X value of the zero (or root) For (X - 1) we then use X=1 For the 1st eqn...

POTENTIAL ENERGY = MGH KINETIC ENERGY = MV2/2 G = 9.8 M/S2 (Gravity accel at earth surface) THE SUM OF POT ENERGY AND KINETIC ENERGY SHOULD BE EQUAL AT POINTS (FROM H=0 - 15M) IN THE FALL. ...

Find the time (answer)

THE PHYSICS EQN IS JUST X = ACC*T2/2 + V*T + X0 FOR BOTH CARS, THEY HAVE NO INITIAL SPEED V1 OR DISPLACEMENT X0 SO X = ACC*T2/2 CAR A HAS ACC = 5.5 BUT LEAVES 1.5 SEC AFTER CAR B CAR B HAS ACC = 4.4 XB...