(9z+8)2 (9z+8)(9z+8) An item raised to the second power is that item multiplied times itself (9z+8)9z + (9z+8)8 Using the distributive property 9z(9z+8) + 8(9z+8) Simply rewriting 9z*9z + 9z*8 + 8*9z + 8*8 Using...

What is (9z+8)^2? (answer)

(9z+8)2 (9z+8)(9z+8) An item raised to the second power is that item multiplied times itself (9z+8)9z + (9z+8)8 Using the distributive property 9z(9z+8) + 8(9z+8) Simply rewriting 9z*9z + 9z*8 + 8*9z + 8*8 Using...

This just an example. Lets say L(y) is the function of getting life insurance. We could go further and say L(y) = 90-y which could be something like the percent chance of getting life insurance where x is your current age. We can see that past a certain age your chance of getting life insurance...

How to mutiply (14x-28y)/[-7(x-2y)] (answer)

There are a few ways to do this. (14x-28y)/[-7(x-2y)] [14(x-2y)/[-7(x-2y)] Factor 14 out of each term of the numerator 14/-7 Cancel (x-2y) out of the numerator...

x+y = 5X-2y = -1 (This is really saying that these three things all are equal.) x + y = -1 5x - 2y = -1 x + y = 5x -2y There are a couple of different ways we can solve this. Substitution: x + y = -1 y = -x - 1 (subtract x from both sides) 5x - 2y...

12-7*6+19-14=11 (answer)

Add the parentheses based on highest order of operation, then left to right. example: 4-3*7-12/6+2 = x 4-(3*7)-(12/6)+2 = x Multiplication and division are higher order than add and subtract, but ...

You're multiplying fractions, like any fractions. The Top time the Top over the Bottom time the Bottom. As for the variables and exponents, you're only multiplying polynomials. Eample ((x2 - 1x - 6)/7x) * ((x+2)2/(4X-2)) ( (x2 - 1x - 6) * (x+2)2 ) / ( 7x * (4x -2) ) ...

factor the expression: x(x-8)+(x-8) (answer)

x(x-8) + (x-8) Looking at you can see that (x-8) is in both terms if you replaced (x-8) with y you'd have x(x-8) + (x-8) xy + y = xy + 1y where y = x-8 y(x+1) factor the y out (x-8)(x+1) simply replace y with it's original value of x-8. You can...

Remember that when multiplying (AX + B)(CX +D) you get (AC)X^2 + (AD + CB)X + BD So I look for the factors of the first and third terms then try to combine them to get the coefficient of the second term. (Hint: Prime Factors are very useful here) Factors of +1...

What we know: 1 ketchup packet has 3/16 oz of ketchup We have 24 oz of ketchup. What were Trying to find out: How...

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