let area of rectangular field be A = xy, where x = length, y = width;
then: A = 3,000,000 = xy ---> y = 3,000,000/x = 3,000,000 x^(-1);
---> L = length of fencing = 2x + 2y + y = 2x + 3y =
2x + 3(3,000,000)[x^(-1)] = 2x + (9,000,000)[x^(-1)];
compute...

x - y^2 = 0 ---> x = y^2 ( parabola opening to the right, vertex at (0,0)) ; let point on parabola that minimizes distance from (0,3) be (a,b); then, slope of line joining (0,3) and (a,b) = m = -(3 - b)/a = (b - 3)/a; using a = b^2, we have the following: m = (b...

I agree with Kenneth S. that since the integrand is an odd function of x, and the integral, call it I, is between symmetrically placed limits, -a and a, the result should be, even without any detailed calculations, I = 0.

perhaps the two curves were f(x) = 2sin((π/2)x), and g(x) = cos((π/2)x); if so, then that would seem to imply that the area in question is:
b
∫ [(f(x) -...

Answer: 9 < A < 11; note that exact answer (area of trapezoid) is: A = 10
details of the above answer, with f(x) = 2x + 3:
using inscribed rectangles: A1 = 0.5[f(0) + f(0.5) + f(1) + f(1.5)] = 0.5[3 + 4 + 5 +...

what's the question?

note the following:
n 2n 2n-1
0 0 -1
1 2 1
2 ...

actually, the work done on a body, W = (component of force in direction of motion)(distance)
= increase...

let x = measure of first angle; let y = measure of second angle; let z = measure of third angle;
then: x = 2y; z = y + 96; and x + y + z = 180 ---> 2y + y + y + 96 = 180 ---> 4y + 96 = 180 ---> 4y = 180 - 96
--->...

what is the question? is the question the following: after one second, what is the velocity of the 10kg mass? if this is
the question, then:
F = ma ---> 5 = 10a ---> a = 0.5 meters/sec^2;
in which case, assuming initial...

let x = cost of one donut; and let y = cost of one large coffee; then
2x + 4y = 5.10; and ---> 2x + 4y = 5.10
6x + 3y = 6.39 --------->...

write sin(7*pi/12) = sin[(3*pi/12 + 4*pi/12) = sin(pi/4 + pi/3) = sin(pi/4)cos(pi/3) + sin(pi/3)cos(pi/4)
= [sqrt(2)/2](1/2) + [sqrt(3)/2][sqrt(2)/2], where we have used sum formula: sin(x + y) = sin(x)cos(y) + sin(y)cos(x)

use Pythagorean Theorem: a^2 + b^2 = c^2, where a = 9, c = 16, and b = ?
then, 9^2 + b^2 = 16^2 ---> b^2 = 16^2 - 9^2 = (16 + 9) (16 - 9) = 25*7 ---> b = sqrt(25*7) = sqrt(25)*sqrt(7)
= 5*sqrt(7)

f(x) = [x - (1 + 2i)][x - (1 - 2i)](x - x1)(x - x2) = [(x - 1) - 2i][(x - 1) + 2i](x - x1)(x - x2) =
[(x - 1)^2 - (2i)^2](x - x1)(x - x2) = [x^2 - 2x + 1 - 4i^2](x - x1)(x - x2) = [x^2 - 2x + 1 -4(-1)](x - x1)(x - x2)
= (x^2 - 2x + 1 - 4)(x - x1)(x...

let x = price of adult tickets, and let y = price of student tickets
then: 64x + 132y = 1040; or, dividing each side of the equation by 4
---> 16x + 33y = 260; this is the equation of a straight line in the
...

let x = number of color copies; and let y = number of black and white copies; then,
x + y = 90 -------------------> 9x + 9y = 9(90) = 810
0.49x + 0.09y = 12.90 ----> 49x + 9y = 1290
subtracting the top equation from the bottom...

the question, presumably, is: what is x, and what is y? assuming this to be the question, then:
x + y = 74 ------------------------> 16x + 16y = 16(74)
12x + 16y = 992 -----------------> 12x - 16Y = 992
subtracting the bottom...

the answer would seem to be 5 bags of oranges on Tuesday, assuming the bags of oranges are of constant size

looks to me like Mark M. is right --->
least amount of time: number of Field Events = 0; number of Track Events = 100; time involved = 100(15) = 1500 min
most amount of time: number of Track Events = 0; number of Field Events = 250; time...

this question seems ill-formed; please clarify