Both of the polynomial pieces must be equal to 11. Thus -7x-2y = 11 and 11x - 2y = 11.
Solve the second equation for -2y by subtracting 11 x from both sides and you have -2y =11+11x
Substitute this into the first equation where the -2y is and you have -7x + 11 + 11x = 11...

Remember to subtract you change the sign and add. Now the problem is 1/(x-3) + -2/(3-x) = 4 (x^2-9).
Next put the minus sign into the denominator of the second term for 2/-(3-x). Multiply the minus sign through the parenthesis to have -3 + x and rearrange x - 3. Now...

Hi Trevor,
You make the polynomial into a square by dividing the second term by 2 and squaring it. 22 divided by 2 is 11. And 11 squared is 121. The completed square for the polynomial is then Z^2 + 22Z + 121. Thus C must equal 121 for the polynomial to be a square...

Maranda,
To answer systems of equaltions by substitution first solve one varible in terms of the other then substitute in for that varible. Here solve x-4y = -19 for x. Add 4y to each side of the equation to have x = -19 +4y. Substitute this in to the original equation...

Long division of a polynomial is very similar to numerical long division. Put the numerator polynomial under the division sign and the denominator on the outside:
_3x^3__-5_________________________
X-2) 3x^4-6x^3-5x+10
...