One bottle of shampoo + one bottle of body wash = 14.50  3 bottles of shampoo and 5 bottles of body wash cost  \$56.90. Rewriting, 3 bottles of shampoo + 3 bottles of body wash + 2 bottles of body wash = 56.90  So, 3x 14.50 +2 bottles of body...

K= z- 1y    = x2 +4x-5- (x2+3x- 4)= x2 +4x-5- x2-3x +4) =x-1   K= x-1

Joe needs 40 min to complete the job  So Joe completes 1/40th of the job in one min.  Similarly, Joe's brother completes 1/50th of the job in one min. so both of them complete (1/40 +1/50)th or 0.045 of the job in one min  thus they together complete the job in...

K= 1/2 mv2   v2 =2K/m   v= √(2K/m)     A= π r2       C= 2π r     r= C/2π Thus, A = π x (C/2π)2               = π x C2/4π2         ...

The equation you need to use for this kind of problems is V1 XS1 = V2 x S2 V1= 8 Lit S1 = 40%. S2 = 10%  you need to calculate V2   V2= (V1x S1)/S2 =( 8 x 40)/10 = 32    Thus you need to dilute 8 lit 40% acid with water to make up the volume to 32 lit (you...

In fact, the correct sequence of the numbers is  84, 14, 12  81, 18, 9 ,88, ?, 11,     If this is the case, the 2nd number = 2(first number/3rd number)  thus, 84/12 x2 =14 ; 81/9 x2 =18, 88/11  x2= 16 so the answer is 16.

The equation of the line P is y= -4.5 x + 4  The equation of the line Q is y= -4.5 x + c  [since it is parallel to the line P] The lile passes through the point (4, -3), Thus, -3 = -4.5X 4 +c thus, c= 4.5x 4 -3 = 18-3= 15 thus the equation of the line Q...

weight of the goid idol = 2 Kg =2000 g which has tobe replaced by the same weight of sand. 2000 g sand = Density of sand x volume of sand    volume of sand = 2000/3 cm 3  = 666.6 cm3  = 0.666 lit

LxW = 24  W= 24/L   2(L+W) =22 so  L+W = 11 L + 24/L =11 L2 + 24 = 11L  L2 -11L + 24 =0 (L-3) (L -8) =0   So L = 3 0r 8  Thus the dimension of the rectangle is 8ft X 3ft

a/sinA =b/Sin B 6/sinA=3/ (1/3) 6/sinA = 9 sinA =6/9 =2/3

x3-3     x2 -2 ⌋ x5 - 2x3 -3x2 +9                x5- 2x3            --------------                ...

-5≤ x-4  -1 ≤ x    x-4 ≤ 13 x ≤ 17 Thus the solution is -1≤ x ≤ 17   Draw a solid line from -1 to 17 on the X axis. That is the solution.      -12≤2-5x   -14 ≤ -5x 14/5 ≥ x   2-5x ≤...

3.86 M K2SO4 contains 3.86 x 174.01 g K2SO4 or 671.6786 g K2SO4 per lit The volume of K2SO4 needed =  72.9/671.6786 = .1085 litre

Slope of the straight line joining two points (x1, y1) and (x2, y2)  is m=  (y2-y1)/ (x2-x1)= (9-1)/(-6-10) = 8/(-16) =-1/2   Thus the equation of the st. line is y = (-1/2)x + c   since the line passes through (10,1), substituting in the above equation,  1...