1+ Sec^2 X. Sin^2 X = 1 + 1/(cos^2 X). Sin^2 X = 1 + Sin^2 X/cos^2 X = 1+ tan^2 X =Sec^2 X
1+ Sec^2 X. Sin^2 X = 1 + 1/(cos^2 X). Sin^2 X = 1 + Sin^2 X/cos^2 X = 1+ tan^2 X =Sec^2 X
We know that the general equation of a line passing through two points (x1, y1) and ( x2, y2) is, (x-x1)/(x1-x2) = (y-y1)/(y1-y2) substituting the values of x1, y1, x2, y2, (x-2)/(2-1)= (y-5)/(5-2) or, x-2 = (y-5)/3 or, 3x-6 = y-5 or 3x-y=1 So the...
vu-4u+2vu-u = vu+2vu-4u-u =3vu-5u =u(3v-5)
If 'h' is the height of the building, and X is the distance, then h/x = tan 35 therefore, x/h= 1/tan35 .....(1) When he moves 100 feet toward the building the angle changes to 400 so h/x-100 = tan 40 therefore ( x-100) /h = 1/tan 40 So x/h-100/h...
If x and y are the number of adult and child tickets then 8.75 x + 3.5 y= 3143....... (1) and, x + y = 460.......(2) Multiplying both sides of the equation with 3.5 we get, 3.5 x + 3.5 y = 3.5 x 460 = 1610.....(3) Subtracting (3) from (1) we have, 8.75 x-3.5 x =...
It will be easier to visualize once you draw a figure. If h is the elevation of the baloon, then, (h-75)/(300)= Tan 200 Therefore, h-75= 300 tan 200 So, h= 75 + 300 x tan200
(Sec x + Csc x)(cos x+ sinx) ..... I used x instead of theata = [1/cos x + 1/sinx] (cosx +sinx) = [(sinx+ cosx)/cosxsinx]/ (cosx+sinx) = 1/cosxsinx =(1/cosx)x(1/sinx)= Secx Cosecx Now you can replace theata for x.
-x2 -1 = -1-x2 = i2 - x2 = (i + x) (i - x )
(8.1x 104 )/(1.8 x10-4) = ( 8.1/1.8)x 104-(-4) = 4.5x108
In 96 years total loss is 9 acres. Therefore yearly loss= 9/96 Acres/year = 0.09375 acres/year If Loss of acreage is L in time "t" years, then L= 0.09375t. So the Equation is A= A0 - 0.09375t where A0 is the initial acreage and A is the acreage after...
Int dx/(sinx+cosx)= Int (cosx-Sinx)dx/(Cos2x-sin2x)= Int cosx dx/ (1-2Sin2x) - Int sinx dx/ (2cos2x-1) ..(.1) Let 1-2sin2x =u and 2cos2x-1 =v so, du= -2 (2)cosx dx =-4cosx dx, thus cosx dx = -1/4 du........(2) and dv= -2 (2) sinx dx = -4sin...
The equations are, 7y=x+2.........(1) and 4x-8y=12......... (2) If we multiply each sides of (1) with 4, we get 28 y= 4x+8, Rearranging, we get 4x-28y = -8 ......(3) Subtracting (3) from (2) we have -8y-(-28y)= 12-(-8) Thus, -8y+28y = 12+8 So...
1/2(7y-2)+1/4(2y+9) = 7y/2 - 1 +y/2 + 9/4 = (7y+y)/2 +9/4-1 = 8y/2 + (9-4)/4 = 4y +5/4
The total amount needed would be 56 X 3 X 2.5 Sq inch =420 sq in =12" X 35" So the minimum size of the metal sheet required is 1ft X 3 ft = 3 Sq ft You can easily cut out 14 strips of 1 ft length. Each of the strips can be cut to make 4 of 3" pieces, thus making a total...
(x-4)² + (x-2)² + (x-3)² = x2 -8x+16 + x2 -4x +4 + x2-6x +9 = 3x2-18x +29
x6-64= (x3)2 - (8)2 = (x3+8) (x3-8) =(x+2)(x2 -2x+4) (x-2)(x2 +2x+4)
(2r + 1 )( r -2 ) = - (3r -6 ) 2r2+ r-4r-2 = -3r+6 2r2-3r-2=-3r+6 2r2=8 r2=4 Thus r= +2 or -2
f(x)=3x+3 is not an equation. It's a line with the slope 3 and an Y-intercept of 3.
9y-5y=8 hence 4y=8 y=2
Hi Jaelyn, Your equation seems to be 13= g/3 +4 and not 13= g/ (3+4) as understood by Marissa. If we rearrange it, g/3= 13-4=9 and hence g=9x3 =27