The probability of winning at least 1 game is equal to 1- P(winning zero games). The probability of winning zero games is (19/20)5 = .774, so the odds of winning at leat 1 game is 1-.774 = .226

The probability of winning at least 1 game is equal to 1- P(winning zero games). The probability of winning zero games is (19/20)5 = .774, so the odds of winning at leat 1 game is 1-.774 = .226

z = kx2/y2 to solve for k substitute the initial values of x , y and z and solve for k 142 = 16k/25 k = 221.875 z = (221.875)(100/36) = 616.32

y=2x+3; y=4x-1 (answer)

Since y = y, 2x+3 = 4x - 1 2x = 4 x = 2, substitute it in and y =7

How many cubes with edge lengths of 1/2 could fit in a rectangular prism with a volume of 2646? (answer)

The volume of the cube is 1/2 x 1/2 x 1/2 = 1/8 2646/(1/8) = 21168

Let b-speed of boat and c=speed of current. Set up a system of 2 equations in 2 variables: 30 = 5(b-c) travelling against the current or 30 = 5b - 5c 30 = 3(b+c) travelling with the current or 30 - 3b + 3c And solve using either elimination...

The probability of the first being black is 6/14 (desired/total). the 2nd is 5/13 (since 1 black marble is gone and the 3rd is 4/12. Multiplying the three together gives us the total probability: 6/14 x 5/13 x 4/12 = 5/91

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When three times a number is decreased by five the square root of the result is 7. Find the number (answer)

sqrt(3x-5) = 7 3x - 5 = 49 3x = 54 x = 18

A=1/2*b*h = 1/2*4.8*5.2 = 12.48 m2

30(3.28)=98.4 ft

First you need to figure out what each column/row is equal to. Add all the number and divide by 3 = 0 Then set up your square -12 0 12 9 -6 -3 3 6 -9 &nbs...

-5a√(12a3b4c) = -5a(2ab2)√(3ac) = -10a2b2√(3ac)

what dimensions should be used to make the gardens, and what will the largest area possible be? (answer)

Let x = length, which is also the shared side. The width will be (200-3x)/4. Area = (l x w) A = x(200-3x/4) A = 50x - 3x2/4 take the first derivative, set = zero and solve for x 50-3x/2 = 0 x = 100/3

A = (pi)r2 = (3.14)(9)2 = 254.34 km2

430/3 = 143.33sq ft of carpeteting Area square = side2 so 143.33 = x2 x= 11.97

0 < x < 17.3

19/4x+1 = 9x+1/5x-1 (answer)

Use cross multiplication: 19(5x-1) = (4x+1)(9x+1) 95x - 19 = 36x2 + 13x + 1 36x2 - 82x + 20 = 0 18x2 - 41x + 10 = 0 solve with the quadratic formula [41 +/- √(412 - 4(18)(10))]/(2(18) (41...

Let x = width, then 3x = length, Area = l x w so, (3x)(x) = 75 3x2 = 75 x = 5 = width, length = 15 Perimeter = 2l +2w = 10 + 30 = 40

Let x = the length of the square cut out of each corner. Then the length/width of our box is 18-2x. To find volume we use LxWxH or: (18-x)(18-x)(x) = x3 -36x2 + 324x Take the first derivative and set it equal to zero to mind the critical values: 3x2...

40p + 55 = 695 (answer)

To solve an equation, you need to isolate the variable on one side: 40p + 55 = 695 First subtract 55 from each side 40p = 640 now diveide both sides by 40 p = 16

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