2 KMnO4 + 16 HCl Produces 2 KCl + 2 MgCl2 + 5 Cl2 + 8 H2O Balanced

2 KMnO4 + 16 HCl Produces 2 KCl + 2 MgCl2 + 5 Cl2 + 8 H2O Balanced

Let x = cost of the chair and y = cost of the table. Set up a system of 2 equations in 2 variables: 2x + 5y = 33 8x + 3y = 30 and solve via elimination (multiply the first equation by 4 and subtract the 2nd equation from the first 8x + 20y...

Let x = width of the walkway Dimensions of garden and walkway is 20+2x and 30+2x find area: (20+2x)(30+2x)-(20)(30) = 336 and solve for x 100x + 4x2 = 336 25x + x2 = 84 x2 + 25x - 84...

a = Pert Use 78 for a, 58 for P and 3 hrs for t, and solve for r (rate): 78 = 58e3r 78/58 = e3r ln(78/58) = ln(e3r) ln(78/58) = 3r r = ln(78/58)/3 = .099 A = 58(e(.099)t)

The position of the falling particle is: x = 0 y = 100-9.8t2 The position of the projected particle is: x = (60cos(60))t = 30t y = (50sin(60))t -9.8t2= 30sqrt(3)t-9.8t2 Think of the distance between the 2 particles as an ever changing...

If sinTheta=12/13 and Theta is in quadrant 2 ,cos2Theta=(blank) and cosTheta=plus/minus(blank) (answer)

If Sin Theta = 12/13, then Cos Theta = 5/13 (5, 12, 13 right triangle). Since the angle is in Quadrant 2, then the Cos would be negative or -5/13. Cos2 Theta = 25/169

Percent = Amount raised/Goal x 100 or x/300 x 100

survey question (answer)

30 - 15 = 15 from TV only

A mass is subject to a force of 200 N east and one of 200 N southwards what is the resultant force? (answer)

The magnitude of the force = sqrt(2002 + 2002) = 282.84 The angle will be (quadrent III): ArcTan(200/200) = -45 degrees = 315 degrees or 7(Pi)/4 Radians

V = (pi)(r2)(h) 12566.4 = (3.14)(r2)(8) r2 = 500.3 r = 22.4 cm

The atomic mass of gold (weight of 1 Mole) is 197g. (197/38)(475) = $2462.50

Let w = width, then l = 2w-4 A=l x w = (2w-4)(w) = 70 2w2 -4w - 70 = 0 w2 -2w - 35 = 0 (w-7)(w+5) = 0 w = 7 or w=-5 (-5 is impossible) w=7

4500-(3245.64 + 650.00) = 604.36

confusion on a word problem. (answer)

You must have 3 pennies so the other 5 coins add up to $0.65. The only way it works is with 2 quarters and 3 nickles.

percent mixture problems (answer)

Let x = # gallons of 25%, then 100-x = # gallons of 75% .25x + .75(100-x) = .6(100) .25x + 75 -.75x = 60 -.5x = -15 x = 30 gallons of 25% 70 gallons of .75%

h(t)=-5t2 + 20t = 0 -5t(t-4) = 0 t=0, t=4

(sin^4X-cos^4X)/sin^(2X-cos^2X) (answer)

I think you want to factor the top as the difference of 2 squares and get: (sin2 x -cos2 x)(sin2 x + cos2 x)/(sin2 x - cos2 x) part cancels out sin2 x + cos2 x = 1

3312 balls/min x 60 min/hr 8 8 hrs = 1589760 balls in 8 hrs 1589760/3 = 529920 boxes / 288 = 1840 cases

The chance of drawing a watch with the first pick is 4/12=1/3, with the second it is 3/11 Multiply these together and get 1/3 x 3/11 = 1/11

factoring quatratic equations (answer)

What is the question?

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