In this problem, you have three unknowns ( number of adults = A, number of children = C, and number of seniors = S). To solve an equation with three unknowns, you need three equations minimum. The first two equations come from the revenue and the number of tickets sold. If the...

Daniela,
Break the problem into two different multiplication problems:
(x4+11x3+33x2+24x+32) * x and (x4+11x3+33x2+24x+32) * 6
multiplying by x is easy, just increase the power of each member of the polynomial. Arrange the...

Lets say that for every city the height of the population is measured. Every city would have a different mean, and the average mean would be the average of the means of each city. In statistics, every trial has a mean, and the average mean would be the average of the means over each...

Sexual reproduction at the molecular level is a very complicated sequents of events. Every gene is found on a specific chromosome. Ther are 46 chromosomes in humans, and each chromosome has a pair, so that there are 23 pairs of chromosomes (there are two copies of each gene). Sex...

You do not need a caluclator for this problem. Group the first two terms together and the second two terms togerter. Factor out x2 from the first two terms and -5 from the second two terms:
(x3+4x2)+(-5x-20) = x2(x+4)-5(x+4)
Because x+4 is a factor of both...

The easiest way to answer this question is to set up a system of equations using the definition of the z-score. The z-score is defined as:
z = (x - μ)/σ
Where x is the value, μ is the mean, and σ is the standard diviation. For a normal distribution, the precentile can...

First, break down this problem into parts. I would break down the problem into Amy's friends, friends of Amy's friends, and friends of friends of Amy's friends.
The first part is easiest, she invites three friends, so all the people Amy invites = 3 = 3^1 where the ^ means that 1 is the...

We should first try to think of a way to form an equation. We'll need to solve for the number of mL from the first solution and the number of mL from the second solution. Because there are two variables that need to be solved for, we'll need to form two equations. Two concepts...