First we must define what it means to be an inverse. If I define a function called "put on my sock" then the inverse would be "take off my sock." This is happening to the foot or the "input." We see that we have f(x)=9x+7 This is telling...

First we must define what it means to be an inverse. If I define a function called "put on my sock" then the inverse would be "take off my sock." This is happening to the foot or the "input." We see that we have f(x)=9x+7 This is telling...

r times Secant theta equals -5 (answer)

If you want it in polar than George and Bill are both right. But just incase you need it in RECTANGULAR then: Given: rSec(θ)=-5 we know that Cos(θ)=x/r since Sec(θ) =1/Cos(θ) then Sec(θ)=r/x so plug rSec(θ)= r(r/x) that means that r2/x=-5 we know...

I need help finding area (answer)

There are a few ways to think of the area of a triangle. I think of a rectangle. if the rectangle has height "a" and length "b" the we know that the area for that rectangle is given as "ab" or a times b. Now if we cut the triangle in half from one corner to another...