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Answers by Arthur D.

I assume that it is a regular polygon. The sum of the measures of the exterior angles of a polygon is always 360 degrees. 360/25=14.4 degrees Each interior angle is... (n-2)(180)=(25-2)(180)=23*180=4140 degrees 4140/25=165.6 degrees for each interior angle each interior angle and it's exterior angle...

(49+49+49+x)/4=37 (147+x)/4=37 147+x=4*37 147+x=148 x=148-147 x=1 yard his fourth throw was only 1 yard look at it this way... an average of 49 in 3 throws is the same as 3 throws of 49 each 49-12=37, 49-12=37, 49-12=37 each throw of...

Trig Identities (answer)

sin(x)=-sin(2x)+sin(5x) rearrange the terms sin(5x)-sin(x)=sin(2x) sin(a)-sin(b)=2cos([a+b]/2)sin([a-b]/2) therefore the left side becomes... 2cos([5x+x]/2)sin([5x-x])/2) 2cos(3x)sin(2x) now we have... 2cos(3x)sin(2x)=sin(2x) 2cos(3x)sin(2x)-sin(2x)=0 factor...

draw a right triangle one side is the height the nest is above the ground-call it n the other side is 15 feet the hypotenuse is the line of sight at 62 degrees tan=opposite/adjacent tan62º=n/15 (15)(tan62º)=n n=(15)(1.880726465) n=28.21089698 n=28 feet above the...

(sin/[1-csc])-(sin/[1+csc])=-2cot^2 rewrite with a common denominator [(sin)(1+csc)-(sin)(1-csc)]/(1-csc)(1+csc)= {(sin)([1+csc]-(sin)[1-csc]}/(1-csc^2)= factor out sin in the numerator (sin)(1+csc-[1-csc])/(1-csc^2)= (sin)(1+csc-1+csc)/(1-csc^2)= (sin)(2csc)/(1-csc^2)= 1+cot^2=csc^2...

Word Problem (answer)

x=side of the square 3x^2=x^2+9x+18 3x^2-x^2-9x-18=0 2x^2-9x-18=0 2*18=2*2*3*3=(2*2*3)*(3)=12*3 and 12-3=9 factor (2x+3)(x-6)=0 x-6=0 x=6 cm check: 6+6=12, 6+3=9, 12*9=108 and 3*36=108