Hi Winston! For a problem like these, your textbook probably gives you a formula. p = x[1 - (1+r)^-n]/r where p is the principal (in this case 15 grand), x is the monthly payment Victor's making (400 or 600), and n is the number of months he's...

Hi Winston! For a problem like these, your textbook probably gives you a formula. p = x[1 - (1+r)^-n]/r where p is the principal (in this case 15 grand), x is the monthly payment Victor's making (400 or 600), and n is the number of months he's...

I love combinatorics problems! I like to think of these problems as "slots" you have to fill with "marbles" you can pull out of a bag. In this case, you have three "slots": first place, second place, and third place. Since there are eight horses competing,...

find the number of numbers that can be 1,2,3,4,3,2,1,by placing the odd digits at odd places (answer)

Hey Manan! This looks like an interesting combinatorics problem, but I don't know if the problem is correctly worded. It's a bit hard to understand. Could you verify that you've written out your question correctly?

The measure of an angle is 21° more than twice it's supplement. Find the measurement of each angle. (answer)

Let's say the angle is x. Then it's supplement would be equal to 180-x. So let's take it phrase by phrase. "The measure of an angle is ..." translates algebraically into "x = ". So moving onto the next part of the sentence, we...

Here's one way of solving this problem: Plant 1 has 28 cars, x of which will be sent to dealership A, and the rest, 28-x, will be sent to dealership B. Transportation cost for Plant 1 to Dealerships A and B will be 220(x) + 300(28-x) Plant 2 has 8 cars, y of which will be sent...

1. s + 4t = r, solve for s Your goal is to get s = something, so isolate the s! Right now, your s is followed by "+ 4t." To get s by itself, you want to get rid of 4t from the left-hand-side of your equation. To that end, subtract 4t from each side of the equation...

You take the same approach as with simplifying other rational expressions like... fractions! Simplifying 15/6 is a no-brainer for most algebra students. One method is to break up both the numerator and denominator into factors. --> (3*5)/(2*3) Obviously, you would cancel...