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Answers by Jennifer K.

Here's one way of solving this problem: Plant 1 has 28 cars, x of which will be sent to dealership A, and the rest, 28-x, will be sent to dealership B. Transportation cost for Plant 1 to Dealerships A and B will be 220(x) + 300(28-x) Plant 2 has 8 cars, y of which will be sent...

You take the same approach as with simplifying other rational expressions like... fractions!  Simplifying 15/6 is a no-brainer for most algebra students. One method is to break up both the numerator and denominator into factors. --> (3*5)/(2*3) Obviously, you would cancel...