Just to add a little detail, the stem and leaf plot gives you the scores for each individual in each class. But the data are arranged in an interesting way that may be a little confusing if you are not used to looking at these plots.
The stem is the tens position and the leaf...

The trick here is to find the factors of the coefficients. For 25 it is (5 x 5) or (-5 x - 5). The factors for -16 are -4 and 4 or (-2 X 8) or (2 x -8).
Now because there is no term with just an x, that is a hint that when this equation was FOILed out the x terms were equal...

Just to be clear then are you saying that the independent variable is which item the respondent completed? That is to say you are comparing scores to each other?
If I am understanding that correctly then you may be interested in conducting a repeated measures ANOVA with something...

First we need to understand the range we are talking about here (4.2 to 5.4) in terms of standardized scores. Then we can use what we know about the normal distribution to estimate the percentage of women who fall in that range.
One way to think about this problem is to try...

This is a question in which you would usually use a table to find the answer. You can use the normal distribution or z tables from the back of most textbooks to find the appropriate cutoff.
Here's a link to a basic table.
http://uregina.ca/~gingrich/tt...

So we have 5√3 x 8√21... The easiest thing to do with a problem like this is to look at the factors for the numbers in the radicals first.
3 doesn't give you a lot as it is prime so it is just 3 and 1.
21 is interesting in that its factors are 3 and 7 both are...

Can't help with the second question as there is no data given. As for the first, I will quickly gloss over the null and research hypothesis.
The research (or alternative) hypothesis is that males and females will differ in their likelihoods of indicating the food is acceptable...

To find the mean use the following formula (∑x)/N or the sum of all x values divided by the number of cases. In this case, N = 77 and ∑x can be calculated in a pretty straightforward albeit time-consuming computations. You can also enter this data into Excel or another statistics program and...

One commonly used statistics package is called R. The upside is that it is free and that it is incredibly versatile and can handle even very complex statistics. The downside is that it can be a little dependent on writing out syntax and code... though this is definitely less of a problem with the...

So it looks like there are multiple parts to this statistics question. The question is whether or not the 5 lb. loss was significantly greater than 2 lbs. Now this seems like a strange number as more often you would be testing to see if the weight loss was significantly different from 0. But alas,...

As this equation is presented there are an infinite number of possible values for x and y that will equal 5/2. X could equal 1 (2/2) and y could be 3/2. Or x could be 251/200 and y could be 249/200 (as just one of the many many values that would make this equation true).
What...

First step is to get everything expanded so you can simplify the answer.
So if you start with 12(1 + 4x) = x - 4 you get... 12 + 48x = x - 4.
The next step is to get all of the x values on one side of the equation and all of the numerical...