Convert to km  75x1.6= 120km then 120/1.5 = 80 km/he to find the speed. distance/hour = speed

Do you need to find x value of the vertex? f(x)=-(x^2+8x-33) f(x) = -x^2-8x+33 vertex = -b/2a your b =-8, a =1, substitute  vertex = -4

Let x will be the first number, create the equation: x^2 +(x+1) ^2 +(x+2)^2=434 x^2+x^2+2x+1+x^2+4x+4=434 combine the terms and solve quadratic equation 3x^2+6x+5=434 3x^2+6x-429=0 divide by 3 x^2+2x-143=0 Solve...

Do square to both sides of equation  sin^2(theta)-2sin(theta)cos(theta) +cos^2(theta) = 2 1 - 2sin(theta)cos(theta) =2 because sin^2+cos^2 =1 2sincos is formula for double angle, so you can substitute: 1-sin(2theta) = 2 -sin(2theta) =1 find 2theta , it...

50/100 =1/2 =0.5

Division

The triangle XOY is equilateral because all angles =60 degree , XO =OY =5 -radius. XY is 5

Discriminant is b^2-4ac from standard form of equation ax^2 +bx +c from your equation: 6^2 -4*5*4 = -46; negative or 46i^2 complex number

What do you need to find?

21/60 x 100%=35%

If chords are ll then alternate interior angels equal each other  ABC equal BCD. angle BAC =90 degree angle BDC =90 degree because both lie on diameter. triangle BAC congruent to BDC because the same side BC and two angles. so AC=BD from congruence of triangles

AO=BO=CO definition of circumcircle which is enter of the circle that passes through all three vertices of the triangle. triangle ABO congruent to triangle AOC because of side and two angles ASA angle ABO=BAO=CAO=OCA so AB=AC from congruence of triangles

35-8=27 44-12=32 27x32 =864 cm^2

Let x to be the speed of the plane in still air. x+30 will be speed with wind x-30 - speed against the wind. since the time will be the same in both directions we can make the equation. the basic formula for rate and time is t=distance/speed 200/x-30 = 300/x+30 solve...

x+y=48 x-y =2 solve the system by adding two equations  2x=50 x =25 y=23

Can be some animal who made the hole in the bag or eat flour.

X^2-4=(x+2)(x-2), so x+2 is the factor.

3y=2x-21 divide the both parts by 3 y= 2/3x -7 where 2/3 is the slope

(k^4-9k^2)+(2k^3-18k)-(15k-135)= k^2(k^2-9)+2k(k^2-9)-15(k^2-9)= (k^2-9)(k^2+2k-15)= (k+3)(k-3)(k+5)(k-3)

Let time = x identify velocity for both ants. first ant has the velocity 139.61/23 =6.07 cm/min the second ant has velocity 88/1.6 =55cm/min they both traveled the same time the equation will look: 6.07x +55x =150.41 solve for x