Gordon, I'm trying to make a doable problem out of your description, but alas I can't. Are you sure you copied it correctly? Jim

I have a line of best fit problem... (answer)

Gordon, I'm trying to make a doable problem out of your description, but alas I can't. Are you sure you copied it correctly? Jim

Simple Math??? (answer)

Kyle, The slanted line forms the hypotenuse of a right triangle and is 53" long the height is 19.2" the width is the other leg of the triangle. Do you recall the Pythagorean theorem? You v=can use it to solve fro the width. &nb...

Lets say the -8 deg occurs at 0800 hrs and you are told that the temperature rose 2 deg every hour so the temperature T(t)=2*(t-8)-8 for t>=8. So at t=8 T(8)=-8 and at t-10 T(10)=4-8=-4 Make sense? Jim

Hi Aleena, The complement of event A is not A and p(A)+p(notA)=1 since the categories are mutual exclusive, i.e. a dog is not a cat. So p(not A)=1-p(A)=1-5/11=6/11. Hope this helps Jim

Hi Anna, I you let w=width and l= length of the panel and p=perimeter =178. Then l=3w-11 and P=2l+2w So 178=2(3w-11)+2w 178=6w-22+2w 178=8w-22 8w=200 w=25" and l=64" Hope this helps Ji...

Hi Dan We know that ax^2 + bx +c =y is the general equation for quadratic function. You were given 4 points if you substuite any three points into the above equation you will have 3 equations for the three unknowns a,b, and c. You can then sub...

Hi Jennifer, First the quadratic is symmetric i.e. when you replace x by-x you get the same result. y(x)=y(-x). whereas the exponential function is not symmetric. Second the quadratic function has no unique inverse but the exponential does ...

Hi Jodie, Let H= no. of chickens C= no. of cows So we know that H+C=29 (each has one head) We also know that 2H+4C=90 ( chickens have two and cows have 4 feet) So you now have 2 equations...

Hi Kinsey, Outside diameter of the tubing = 3 1/4" The outside radius is 1 5/8" (half the diameter). To find the inside radius we subtract the wall thickness from the outside radius which is 1 5/8 - 3/16 =1 7/16". to find the inside...

Take 1/2 the coefficient of x and square it (40/2)2 =400 Rewrite the equation adding and subtracting 400, (x2+40x+400)+c-400 This can be written as (x+20)2 +c-400 from which you can find the roots (x+20)2=400-c by taking+- the square root of both sides and solve...

Tanner, You calculate the discounted cash flow for each time period and just add them up. When summed over all the time periods this quantity is sometimes called the "net present value" of the investment. Jim

Jason, If the the ball drawn was replaced this would a Bernoulli trail (independent trials and success probability is constant) then you would use at the binomial distribution. Since the success probability is not constant as mentioned in the other answers, you would...

Zoe, Lets divide the rod into two segments left and right at .25m and .75m The center of mass of the segments are at .25/2 and .75/2 Taking moments (torque) about the given point gives ,25mg(,25/2)-.75mg(.75/2)=.6125-5.5125=4.9 N-m which is g/2 m=2kg...

The electric field E is defined by the force F it exerts on a positive test charge Qo. E=F/q0 and it is a vector. Hope this helps Jim

I need a little physics help (answer)

Nana You have 3000=7.5*t2, so t=(3000/7.5)1/2 use your calculator. Jim

Solving by subsitution (answer)

John, Since x-y=0 then x=y from the first equation Putting x=y in the second equation gives -6y+5y=4 so y=-4 and x=-4. The idea is to solve one of the equations for one of the unknowns and substuite that relationship in the second equation...

Permutation or Combination? (answer)

Ruth, If you picture all the contestants on the x and y axis on the integer coordinates then each lattice point is a potential confrontation. Some points should be excluded 1. points on the diagonal represent confrontation with oneself (1,1) (2,2)... so there are 24...

Hi Deoni, Centripetal acceleration is the acceleration required to keep a particle moving in a circle. It (the vector) always points toward the center if the circle and has magnitude v2/R where v is the speed of the particle and R is the radius of the circle. ...

P=2I+2W to solve this equation for W you do whatever you need to to isolate W so subtract 2I form both sides: P-2I=2W since 2I-2I=0 the divide both sides by2 :(P/2)-I=W and there you have it w=(P/2)-I now you can put the numerical values for P and I in this equation...

Pi Problem (answer)

The two straight sections =171 m so the 2 half circles must measure 400-171=229m so if the radius of the circle is R then the circumference is 2*π*R and this must be equal to 229m so R=229/6.28...=36.45 m Hope this helps Jim

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