Search 80,000+ tutors
FIND TUTORS
Ask a question

Answers by Jim S.

Gordon,            I'm trying to make a doable problem out of your description, but alas I can't. Are you sure you copied it correctly? Jim

Simple Math??? (answer)

Kyle,         The slanted line forms the hypotenuse of a right triangle and is 53" long the height is 19.2" the width is the other leg of the triangle. Do you recall the  Pythagorean theorem? You v=can use it to solve fro the width.   &nb...

Hi Aleena,           The complement of event A is not A and p(A)+p(notA)=1 since the categories are mutual exclusive, i.e. a dog is not a cat. So p(not A)=1-p(A)=1-5/11=6/11.   Hope this helps   Jim

Hi Anna,           I you let w=width and l= length of the panel and p=perimeter =178. Then l=3w-11 and P=2l+2w So 178=2(3w-11)+2w 178=6w-22+2w 178=8w-22 8w=200 w=25" and l=64"   Hope this helps   Ji...

Hi Dan           We know that ax^2 + bx +c =y is the general equation for  quadratic function. You were given 4 points if you substuite any three points into the above equation you will have 3 equations for the three unknowns a,b, and c. You can then sub...

Tanner,        You calculate the discounted cash flow for each time period and just add them up. When summed over all the time periods this quantity is sometimes called the "net present value" of the investment.   Jim

Jason,       If the the ball drawn was replaced this would a Bernoulli trail (independent trials and success probability is constant) then you would use at the binomial distribution. Since the success probability is not constant as mentioned in the other answers, you would...

John,      Since x-y=0 then x=y from the first equation   Putting x=y in the second equation gives -6y+5y=4 so y=-4 and x=-4.   The idea is to solve one of the equations for one of the unknowns and substuite that relationship in the second equation...

Ruth,       If you picture all the contestants on the x and y axis on the integer coordinates then each lattice point is a potential confrontation. Some points should be excluded 1. points on the diagonal represent confrontation with oneself (1,1) (2,2)... so there are 24...

Hi Deoni,         Centripetal acceleration is the acceleration required to keep a particle moving in a circle. It (the vector) always points toward the center if the circle and has magnitude v2/R where v is the speed of the particle and R is the radius of the circle.  ...

P=2I+2W to solve this equation for W you do whatever you need to to isolate W so    subtract 2I form both sides: P-2I=2W since 2I-2I=0  the divide both sides by2 :(P/2)-I=W and there you have it w=(P/2)-I now you can put the numerical values for P and I in this equation...

Pi Problem (answer)

The two straight sections =171 m so the 2 half circles must measure 400-171=229m so if the radius of the circle is R then the circumference is 2*π*R and this must be equal to 229m so R=229/6.28...=36.45 m   Hope this helps   Jim