If you expand each side you have x2+2ixy-x-y2+iy=0 now you can solve this equation as a quadratic which has two solutions. Jim
If you expand each side you have x2+2ixy-x-y2+iy=0 now you can solve this equation as a quadratic which has two solutions. Jim
Brianna, 6-x>15 so we are looking for any and all the numbers x that when subtracted from 6 are greater than 15. Lets try x=4 and see if that is a possible solution i.e. 6-4=2 and 2 is not greater than 15 so x=2 is not a possible solution. We...
Earnings measures are usually stated at year end so use share price on 12/31 and shares outstanding from the 12/31 balance sheet. Hope this helps Jim
Sarita, The jumper's Kinetic energy 1/2m v2=mgh where h=42' and m=150/32.2 slugs at this point you have a moving mass starting to stretch a spring (assume linear) so the kinetic energy will be transferred to potential energy by stretching the spring so we have...
Nicole, You can attach your documents to a WyzAnt email. Jim
Dana, The midpoint of sales is (19,580+35,139)/2=27,359.50. If sales follow a liner pattern then sales in 2006 would be $27,359.50 Hope this helps Jim
Dion, To integrate a function like √(x5) you can express it as x5/2 and us the rule for integration exponents i.e. ∫xadx=(1/a+1)xa+1+constant Jim
Mayra, Always willing to help a solder (my son is active Army). I tutor Physics, math and statistics. Let me know what you need and we can work out an arrangement. Jim
If y=8/x then 2x+y=2x+8/x and as you can see when x is small and >0 this function is large and when x is really big and >0 this function is large again so somewhere in between this function has a minimum value. To find it you differentiate with respect to x and set the resulting function...
Hey Jammy, Is this a trick question?? Usually the main reason is you want or need to know the answer.. Jim
Hi Sydney, I think part of the question is missing.....that being the null hypothesis. Since the significance level of .01 was used the researcher wanted to take precaution the likelihood of a type one error was small. A type one error is rejecting...
Amanda, Not sure why you want to rationalize the radical in the numerator?? You can find the limit as x→0 by applying l'Hopital's rule i.e. take the limit of the derivative of the numerator divided by the derivative of the denominator. I got...
Kia, Assuming that passing the quiz is a grade of 70% we have to have the average of the 10 questions be .7 or (1+1+x)/10=.7 where x is the number of correct in the remaining 8 questions. Solving for x gives x=5. So she has to get at least...
Assuming that birth of each child is an independent event and that the probability of a girl is 1-.47=.53 (assumes probability of a miscarry =0) then the probability of exactly seven successes in 12 tries is 12C7*.537*.475=.213... Hope this helps Jim
Stephanie, The complex number z=-5-2i can be though of as a vector in 2 dimensions with an x component of -5 and a y component of -2. If you plot this point you will see that it falls in the third quadrant. To express this in polar form r,θ first calculate r=(52+22)1/2=5.38.....
Jackie, 20% more than 50 is 1.2*50=$60 This is the upper limit on Evans spending. So Evan spent <$60. Jim
Dean, To simulate the red light encounters use the function "rand" which generates a random number between 0 and 1. Copy this down 100 rows in column A, in the next column use an indicator "if(A1<.3,1,0) which returns a 1 when the value in...
Hi Jacklen, Assuming the pyramids are square with side s and slant height h the volume is v=h*s2/3. You were given the ration of two pyramids and were told they were (geometrically) similar so s1=k*s2 and h1=k*h2 where k is called the scale factor. So now we can write v1=h1*s1/3...
Robert, Assuming that the .88 probability is generally applicable to students in the particular term, and assuming test takings are independent events i.e the probability of me following instructions will not influence you following instructions. We can use the binomial...
You want to find integers p,q such that p+q=7 and p*q=3, if you plot q=7-p and q=3/p on the same graph and find out where the line and the curve intersect you will quickly find out there are no integer solutions. Jim