Obviously this isn't me presenting this, but this is a very clear and concise video on how to do this:
http://www.virtualnerd.com/pre-algebra/factors-fractions-exponents/prime-factorization-greatest-common-factor/greatest-common-factor/greatest-common-factor-monomials
To put it...

No matter what, it will cost 174.20 per month for insurance and payment. Whether you drive the car 1 mile, or 1000 miles, you will pay 174.20 per month for this. That makes 174.20 your "constant" figure. Miles driven can vary month to month, so this will be your variable...

Think of the smallest prime number that 272 can be divided by, then divide it by that number. Since prime numbers can only be divided by themselves and 1, you don't have to worry about simplifying the number you divided by. Replace 272 with the answer you got when you divided, and repeat...

In the first two questions, you need to find out how much each company charges for the number of hours of work. Then you can add any extra fees on top of what your answer for each company is. Whichever company you can get the cheapest would be the better deal.
For the third question,...

When multiplying polynomials such as (3x + 7) * (x^2 - 3x + y), you multiply every expression in the first one by every expression in the second one, so you end up with
3x*x2 + 3x*(-)3y + 3x*y +
7*x2 + 7*(-)3x + 7*y. The (-) means "negative" and not...

First you cross multiply, then solve for the variable:
If given a/b = c/d (a is the variable in this example, which is why it is
bold) you would multiply a and d, and b and c so it ends up being
a*d = b*c, then you solve for a. So if it were a/2 = 3/6, you would end up with:
6a...

First you should use the smallest bill to until you get to a difference that is divisible by both of the larger denominations. Set this amount aside because you know these bills will definitely be in the final count. Then use the largest denomination to get the difference in the $61...