The method you owuld use to get to the answer is to plug in the vales for x and y (given by the points of each letter as (x,y), perform the operations and see if you have a true statement,
Testing with letter C (3,2) proves correct, since
2x + y = 8
2x3 + 2 = 8
6 + 2...

Solving this type of problem gets more simple if one seperates the dimnsions of motion and determines which order to solve the problems in.
(b) seems easiest from first glance
V0x = 20 cos 45 = 14.14 m/s, dx = vx t, so t = dx / vx = 3.8 m / 14.14 m/s = 0.27 s
this means it takes 0.27...

use and re - use the slope formula and then the point slope formula
these formulas will come in handy
slope, m = (y2 - y1) / (x2 - x1) = (-5 - 3) / (3 - 0) = -8 / 3
now you have both a point and the slope, so use the point slope formula. either point will work but choose the point with...

Newton's 2nd Law is the source for all the figuring in physics. It states that any acceleration of an object (acceleration is a vector with both magnitude and direction) will be in the direction of the net force (a vector as well), and will be directly proportional to the net force, and inversely...

One real life situation of an ellpse involves planet paths of revolution around the sun. Peek at the following websites.
http://www.cso.caltech.edu/outreach/log/NIGHT_DAY/elliptical.htm
http://www.analemma.com/Pages/EllipticalOrbit/EllipticalOrbitEffect/EllipticalOrbitEffect.html

First method to determine answer is to use FOIL method -
18 u v = 18 (2-2i) (1-1i) = 18 (2-2i-2i-2) = 18 (-4i) = -72i, this means magnitude of 72 units along the i - axis pointed down from the orgin.
Second method to do this involves multiplying phasors (multiply magnitudes and add angles)...

a) to get the period of the motion, find the distance involved in one complete cycle d = 2*pi*r. since this is constant speed, the time for one complete cycle is T = d/v = 2*pi*r / v. substitute to get 10.8 s.
b) while the addict traverses the circular path, two forces act on the addict...

The key here seems to be to solve for the acceleration of the system of three blocks. The blocks will accelerate in unison. m3 will drop with a (m/s^2). (m1 +m2) will head to the right with the same a (m/s^2).
This being the case, it helps to do a free body diagram with the down directon...

start with factors of 10: (1,10), (2,5)
and factors of 35: (1,35), (5,7)
little bit of trial and error works since there are so few factors
middle two terms of FOILing binomials must sum to -11.
one binomial must be +, and the other -.
(2w - 5x) (5w +7x) = 10w^2 +...

if a simple algebraic equation you isolate e by subtracting 12.2 from both sides. e = 27.8
if an exponential equation with an exponent variable such as
e^x + 12.2 = 40
then subtract 12.2 from btoh sides to place in BEN form Base Exponent Number
e^x = 27.8
then take the ln...

Polar form
Magnitude = sqrt(2^2 + 2^2) = sqrt(8) = 2sqrt(2)
Angle = tan-1 (2/-2)CALCULATOR FEEDS BACK -PI/4, BUT KNOW BETTER BECAUSE IT IS A 2ND QUADRANT ANGLE = 3PI/4.
This means problems translates to (2sqrt(2))^8 * e^i(3PI/4)^8
(2sqrt(2))^8...

+3 and -5/2 are the roots of the equation.
this means that the quadratic equation has factors
(x-3)((x+5/2) = 0
relatively straightforward to FOIL thes binomial factors to get
x^2 + (5/2 x - 3x) -15/2 = 0
combine...