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Also, you have two different equations there. If you wanted to factor the first one (the one with 13 in it) you'd need to find two numbers that multiply together to give 40 AND add together to get 13. When I look for that combination, I find 8 and 5. So one of your factors is (x+8) and the...

This is a question dealing with combinations and permutations.  It sounds like it's a two-part question; first you have to figure out how many different possible lineups there are.  Then, you have to figure out how many seasons that will fill up.  The first part is the only really...

Without specifically giving you the answers, let me see if I can point you in the right direction.  When the question talks about the "solutions," it's referring to the value or values of x.  a and b are constants, so they would in reality be replaced with numbers.  The...

This problem comes from a fun little branch of mathematics called "combinatorics."  Basically, they want to know how many different combinations you could make out of the letters of the alphabet, given that they're all lowercase and no repeats are allowed.  So let's put six...

These are all great answers, but I'd like to point out something a bit more conceptual.  The skills learned in algebra are based on the idea that you can manipulate an equation by doing the same thing to both sides to create another equation that's the same value, but written differently...

The key to this one is figuring out what percent of the students are NOT in the play.  If 30% of the students are in the play, that means that 70% are not, right?  And we know that 140 students are not in the play.  So 140 people is 70% of the total students, which is what we want...

Hi Willie,   Well, your first step should be to figure out how much each chocolate bar costs Fred when he purchases them from the school in boxes.  If there are 24 bars in a box and the box is \$12, that means each bar costs him 50 cents in the box, right?   So knowing...

This sounds like the entirety of most textbooks' chapters on geometric proofs.  I assume you have a textbook for your math class, right?  I'd just find the chapter on proofs and read through it carefully - most of the terms you mentioned have simple one or two-sentence definitions which...

Hi Ma,   This is a simple system of equations.  The tricky part is translating the word problem into the equations in the first place.   So we know two different things about this matinee showing - we know the total ticket sales, and we know how many people attended...

Just to tack onto Keshab's answer, since you didn't specify exactly what the problem was looking for, here's a couple of things you'd know by that point:   If you're looking for the solutions when the original equation = 0, that means that one of those two factors must come out to zero...

The trick to this problem is finding the lowest common denominator so that you can work the problem algebraically.  First, we should distribute the 3/5 through the parentheses, just as if it weren't a fraction at all.  Just be sure you're multiplying all the parts correctly, and you'll...

Hi Joe,   This problem is a simple matter of plugging expressions into a formula and doing some basic algebra.   First, ask yourself what's the formula for the area of a rectangle?  It's just length times width, or l * w.   They've told you values for...

Hi Theresa,   Hope this helps you figure out not only the answer to your problem, but how to do these types of problems in general.   So, you need to find the 4th root of 1296, which means you need to find two or more numbers which, in addition to multiplying together to...