If there is no solution, enter NO SOLUTION.) 2 -2 sin t = 2 sqrt(3)cos t My solutions were pi/2, 7pi/6, and 11pi/6.
If there is no solution, enter NO SOLUTION.) 2 -2 sin t = 2 sqrt(3)cos t My solutions were pi/2, 7pi/6, and 11pi/6.
Please help, I have no idea! Solve the following trigonometric equation sin^2x - cos^2x = 1/4.
(secθ-tanθ)^2=2secθtanθ
I can find x = 0, and also can show that cos x = (1/4)*(-1+/-sqrt(5)), but I don't know how I should have known that the latter cosines of x correspond to angles involving fifths of pi (radians)...
(show work) where 0≤x<2π
Prove 1 - sin2x / cosx = sin2x / 2sinx I tried do both LHS and RHS. Got stuck after a step or two.
tan3x - tan2x- tanx = tan3xtan2xtanx
Prove a^2(1+cos)=1-cos if 1-a^2)sin - 2acos =0
Explain how you could determine the exact value of (sec 7pi/6) if you know the value of (sin 11pi/6). Prove with diagrams. I've no idea how to do this question that's worth 10 marks...
This is for my trig class, and the directions say to verify the identity. Thanks so much.
sin(X)sec(x)=1-(cos^2)x/sin(X)cos(X)
This is for my trig class. Thanks for the help!
This is for my trig class. Thanks for the help!
Complete the identity: csc(t)(sin(t) + cos(t)) = ?
1) given the double angle identity for cosine: cos2θ=cos2θ-sin2θ Prove: cos3θ = cos3θ - 3cosθsin2θ and: cos4θ = cos4θ - 6cos2θsin2θ + sin2θ 2)...
2sin^2x - 1÷ sinxcosx = tanx-cotx
cosx = (1- tan^2 x/2) / 1 + tan^2 x/2) Completely stuck.
Prove sec2x = 1 + tan2x I did R.H.S = 1 + sin2x / cos2x = 1 + (1 - cos2x) / (1 - sin2x) = 1 + cot2x = ??? I think I'm doing it right,...
∫1 1 dx =¶ + 1 0 (1+x2)2 8 4
Prove that 1 +sin b -cos b=2sin 1 b cos 1 b +sin 1 b ...