If there is no solution, enter NO SOLUTION.) 2 -2 sin t = 2 sqrt(3)cos t My solutions were pi/2, 7pi/6, and 11pi/6.
If there is no solution, enter NO SOLUTION.) 2 -2 sin t = 2 sqrt(3)cos t My solutions were pi/2, 7pi/6, and 11pi/6.
Please help, I have no idea! Solve the following trigonometric equation sin^2x - cos^2x = 1/4.
(secθ-tanθ)^2=2secθtanθ
I can find x = 0, and also can show that cos x = (1/4)*(-1+/-sqrt(5)), but I don't know how I should have known that the latter cosines of x correspond to angles involving fifths of pi (radians)...
(show work) where 0≤x<2π
tan3x - tan2x- tanx = tan3xtan2xtanx
sin(X)sec(x)=1-(cos^2)x/sin(X)cos(X)
This is for my trig class. Thanks for the help!
This is for my trig class. Thanks for the help!
This is for my trig class, and the directions say to verify the identity. Thanks so much.
1) given the double angle identity for cosine: cos2θ=cos2θ-sin2θ Prove: cos3θ = cos3θ - 3cosθsin2θ and: cos4θ = cos4θ - 6cos2θsin2θ + sin2θ 2)...
(1-cos^2x)(cot^2+1) = 1
2sin^2x - 1÷ sinxcosx = tanx-cotx
cosx = (1- tan^2 x/2) / 1 + tan^2 x/2) Completely stuck.
Explain how you could determine the exact value of (sec 7pi/6) if you know the value of (sin 11pi/6). Prove with diagrams. I've no idea how to do this question that's worth 10 marks...
Prove 1 - sin2x / cosx = sin2x / 2sinx I tried do both LHS and RHS. Got stuck after a step or two.
Prove sec2x = 1 + tan2x I did R.H.S = 1 + sin2x / cos2x = 1 + (1 - cos2x) / (1 - sin2x) = 1 + cot2x = ??? I think I'm doing it right,...
∫1 1 dx =¶ + 1 0 (1+x2)2 8 4
Prove that 1 +sin b -cos b=2sin 1 b cos 1 b +sin 1 b ...
Jay is 120 meters from the base of a building and Mary is 40 meters from the base of the building. Jay's angle of elevation when looking at the top of the building is X and Mary's is 2X. What is the...