solve the equation for the solutions over the interval [0 degrees, 360 degrees) 6sec2xtanx=12tanx I am unsure of where to begin.

solve the equation for the solutions over the interval [0 degrees, 360 degrees) 6sec2xtanx=12tanx I am unsure of where to begin.

Two skydivers are falling straight down, aiming for a target which is 2.5 km due West of both of them. They both measure the angle of depression to the landing area. If the measured angle is 38° for...

cos(3theta)=-1 solve for exact solutions over the interval [0,360 degrees] I am having trouble finding a place to start.

Theta=51degrees opposite=15 sin theta=????

I am getting stuck at 7 plus or minus sqrt 309 / 26 13sin^2x-7sinx=5 solve for interval [0,360degrees]

they are squared and to the power of 4

No further details.

a bush walker walks 14km east and then 9km south. find the bearing of his finishing position from his starting point

airplane leaves from the angle of 11 degree with speed of 84 metres per second. find the height of the after 4 mins

Please answer as soon as possible!

Please answer as soon as possible! Thank you so much!

I have no idea how to solve this :(

Side of square is 1cm and perimeter of triangle PAQ is 2 cm

isoscels triangle

Given that csc a = sec 1.45 and that a lies in the first quadrant, use a cofunction identity to determine the measure of angle a, to two decimal places

Twice a first number decreased by a second number is 6. The first number increased by four times the second number is 39. Find the numbers

i need a answer for this, i am missing this question in a work and can not solve it it can affect my grade can you please solve it please?

Equation: log16 2 = 1/4 Choices: A) (1/4)^2 = 16 B) 161/4 = 2 C) 162 = 1/4 D) 216 = 1/4

Haley is standing on the roof of a building 100.0 ft. above the ground looking down at the building next door. She finds the angle of depression to the roof of that building from the roof...

A pedestrian walks East at the rate of 6 km per hour. The wind pushed him NorthWest at a rate of 13 km per hour. Find the direction of the resultant vector. (round to the nearest tenth) I...