sin^2x-cos^2x=2sin^2x-1 (tanx+cotx)/tanx=csc^2x

sin^2x-cos^2x=2sin^2x-1 (tanx+cotx)/tanx=csc^2x

I'm having trouble trying to prove this trig identity. Help is greatly appreciated. Thanks in advance. 1/(csc-cot) = (1+cos)/sin

Use the trigonometric identities to write each expression in terms of a single trigonometric function. A. Sin^2 D. (tan^2 +1)Sin^2 Cos^2 B. cot +1 E. 1+ 1 tan +1 cot^2 C. Sin^2 +cos^2...

help please

I am very confused as to what identity I need to use to simplify this equation.

help please

Please help

prove (1 - cos2x)(1 - tan2x) = sin2x cos2x/1-sin2x I got as far as.... Using the left side: (1 - cos2)(1 - tan2) (1 - cos2)(1 - sin2/cos2) 1 - cos2 - sin2/cos2...

When verifying trigonometric identities, can you multiply both sides by a number to make it easier to solve?

A: -√(17/24) B: -√(7/24 C: -√(7/6) D: -√(17/6

Use knowledge of trig identities to find the trig value below. If csc α = 5/2 , find sec α cot α

I have a math problem in which I have to prove the identity sin2θ= 2tanθ/1+tan2θ using Double-Angle Identities and I'm trying to figure out how to solve it.

My math is online and the helper says that sin∅= y/r= (5√74)/74 = 144.5° . how do u convert that fraction into degrees. I did try the inverse of ∅=sin-1(y/r) , but for my example that...

If csc ∝ = 7/4, find cos∝cot∝ + sin∝. Please include steps. I don't know how to go about this one.

Proved LHS is RHS

Prove: tanA + cotB= cos(A-B) / cosAsinB

A) -1 B) 1 C) 0 D) undefined E) none of these

to prove: (tan(x)+sec(x)-1)/(tan(x)-sec(x)+1)=sec(x)+tan(x)

Write the following in terms of sin (theta) only: 2sec(theta)tan(theta)+tan^2(theta)

prove (1 - cos2x)(1 - tan2x) = sin2x cos2x/1-sin2x I can't seem to solve this! Halp!!!

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