Using either the sums as products or products as sums to work out the answer.

Using either the sums as products or products as sums to work out the answer.

if sin of A = 5/13, in quad 1, find tan A/2 if cos of A = -4/5, in quad 2, find sin A/2 if cos A =-4/5 in quad 2, find cos A/2 if cos A - -4/5 in quad...

Is it that the line of the tangent in the graph will be a continuous or broken

Solve the equation 8sin(1/2)x - 5 = 0 for 0 < x < 2pi. Round your answers to the nearest hundredth of a radian.

State the amplitude and period of this function: y = -3cos(pi/3)x.

State the amplitude and period of this function: y = 4sin(1/2)x

cotxsinx=cosx also tanxcotx-cos^2x=sin^2x

Suppose that 𝒗 and 𝒘 are unit vectors. If the angle between 𝒗 and 𝒊̂ is 𝛼 and that between 𝒘 and 𝒊̂ is 𝛽, prove that cos(𝛼−𝛽)=cos𝛼cos𝛽+sin𝛼sin𝛽

I missed this class so I'm really confused on how to solve this.

I am doing sum and difference formulas with sin, cos, and tan. I am doing tan75 with the difference formula. So tan 120-45 I have all the things found I just don't know...

3(sec^2Θ - tan^2Θ)/ 2sec^2Θ a. 3/2cos^3Θ b. 15/2cos^5Θ c. 3/2cos^3Θ

I am using trigonometric identities like the fundamental identities and pythagorean-rules to substitute/cancel terms until I end up with the same thing on the left of the equation as I have on the...

the 14 in the equation is supposed to be under a radical i just couldn't do that on my computer

I'm really confused on how to solve this.

Can someone explain to me how you would establish this identity: cos(a-B)•cos(a+B) = cos^2a - sin^2B

Please include each step so I can follow along

In this problem angle theta must be greater than 0 and lesses than 2 pi

The questions are: "If sin B = -1/3 with B in QIII, find tan B/2. Also find sin B/2 The answer for tan B/2 is-3-2sqrt(2) The answer for sin B/2 is \sqrt((3+2\sqrt(2))/(6)) These...

If sinθ=5/13 is in quadrant 2, what is the value of sin(θ+3pi/2)?

The question is cos -105. I know how to do the process for it but for some reason my answer doesn't have the right negatives. I am getting: √2 + (-√6) -------------- ...

simplify and show all work please