Exact value of Sin pi/12 I got this answer to be (√6 - √2 )/4 (part a) I then done the half angled identity to be √(2 - √3)/2 (part b) Both...
Exact value of Sin pi/12 I got this answer to be (√6 - √2 )/4 (part a) I then done the half angled identity to be √(2 - √3)/2 (part b) Both...
I need to express cos(theta) in terms of sin(theta) only. Thank you in advance for your help.
how do you find the angle of a triangle with sides (6u-1) and (1u) and an area of 5cm^2 ? there was a question like this in a test i did but i couldn't work out the...
Please Help. Establish Identity: sin(x+y)/tan(x)+tan(y)= cos(x)cos(y)
(1/sinx + 1/cosx)/(1/sinx - 1/cosx) = (cos2x-sin2x)/1-2cosxsinx)
cos2 x + (sin x + 1)2 / sin x + 1
I know that this can be expanded to (sin2x+cos2x) (sin2x+cos2x)=1, which can be multiplied to be sin^2(4x)+2sin(2x)cos(2x)+cos^2(4x)=1. Or am I missing something here? I'm not...
Given cos(alpha)=5/6 and alpha is in quadrant I, find the exact value of cos(alpha/2). Note: You are not allowed to use decimals in your answer.
tan(x) + 1 / sec(x) = sin(x) + cos(x)
Proving Basic Problems: I have to prove that one side equals the other using identities. √(3cosx+4sinx)2+(4cosx-3sinx)2 = 5 Please show the steps or even try...
(1/2)sin(2x) / sin2 x
1 - (sin(A) + cos(A))^2
sect - 1/sect + 1 = A - cost/A + cost Find A.
Let again t be the angle between 0 and \frac{\pi}{2} such that sin t = 1/4 Then cos (t+pi) = . sin(t-pi) = . cos (t+2pi) = . tan (t+pi) =
1. Reciprocal Identity: csc (A) = 2. Reciprocal Identity: cot (A) = 3. Ratio Identity: cot (A) = 4. Pythagorean Identity = 1 - cos^2(A) = 5. Pythagorean Identity = 1 +tan^2(A)...
1. sec (x) / tan(x) 2. sin (x) / csc (x) + cos ^2 (x) 3. sin (x) / csc (x) - sec (x)cos (x)
I need to see all the steps for this question so I could be able to it on my own next time. Show me in full detail of how you arrive at the answer. You have to find the sign A (input + or -) ;...
How do I distribute (cosxcotx)(secx-tanx)?
i know that cos(a-b) = cosacosb+sinasinb And cos(a+b) = cosacosb-sinasinb and cos(x+x) = cos^2x-sin^2x
I know you are supposed to us the trig identities, but I have know idea where to even begin.