I missed this class so I'm really confused on how to solve this.

I missed this class so I'm really confused on how to solve this.

I am using trigonometric identities like the fundamental identities and pythagorean-rules to substitute/cancel terms until I end up with the same thing on the left of the equation as I have on the...

the 14 in the equation is supposed to be under a radical i just couldn't do that on my computer

I'm really confused on how to solve this.

3(sec^2Θ - tan^2Θ)/ 2sec^2Θ a. 3/2cos^3Θ b. 15/2cos^5Θ c. 3/2cos^3Θ

I am doing sum and difference formulas with sin, cos, and tan. I am doing tan75 with the difference formula. So tan 120-45 I have all the things found I just don't know...

Can someone explain to me how you would establish this identity: cos(a-B)•cos(a+B) = cos^2a - sin^2B

Please include each step so I can follow along

In this problem angle theta must be greater than 0 and lesses than 2 pi

The questions are: "If sin B = -1/3 with B in QIII, find tan B/2. Also find sin B/2 The answer for tan B/2 is-3-2sqrt(2) The answer for sin B/2 is \sqrt((3+2\sqrt(2))/(6)) These...

If sinθ=5/13 is in quadrant 2, what is the value of sin(θ+3pi/2)?

The question is cos -105. I know how to do the process for it but for some reason my answer doesn't have the right negatives. I am getting: √2 + (-√6) -------------- ...

simplify and show all work please

simplify and show all work please

How do I rewrite (tanθ+secθ)/cosθ in terms of sinθ? (fully simplified)

Prove each of the following identities

4 sin x cos x - 2√3 sin x - 2√2 cos x +√6=0 interval 0≤x<2pi

This is translated from a trigonometry problem in another language, I hope you understand it.

If csc(α) = 3, where 0 < α < π/2, and β is a Quadrant II angle with tan(β) = −7, find cos(α+β) And there are others that I'm supposed to find, such as sin(α+β),...

This is my work. tanx = -2sinx sinx/cosx = -2sinx sinx = -2sinxcosx (multiply by cosx) 1 = -2cosx (divide...

I am getting stuck at 7 plus or minus sqrt 309 / 26 13sin^2x-7sinx=5 solve for interval [0,360degrees]