sinΘ⁄ 1+cosΘ + 1+cosΘ/ sinΘ = 2cscΘ

sinΘ⁄ 1+cosΘ + 1+cosΘ/ sinΘ = 2cscΘ

1 + tanΘ / 1 + tanΘ = tanΘ

5tanx = 2sinsx solve for interval (0 2π) algebraic means without calculator

cos2x = cosx solve for interval (0 2π) algebraic means without calculator

5tanx = 2sin2x solve for interval (0 2π) algebraic means without calculator

sin4x - sin2x = 0 solve for interval (0 2π) algebraic means without calculator

sin x- sq root 3 cosx = 0 solve for interval (0 2π) algebraic means without calculator

sin (x/2) = 1- cosx solve for interval (0 2π) algebraic means without a calculator

(sinx+siny)/(cosx-cosy) = -cot(x-y/2) use left as given

sinxcosy = (1/2)(sin(x+y)+sin(x-y)) left side is the given

(1+cosx)/(sinx) + (sinx)/(1+cosx) = 2cscx use left side as given

Verify the Identity.

Proving a trig identity and I dont know what to do

I'm having trouble trying to prove this trig identity. Help is greatly appreciated. Thanks in advance. 1/(csc-cot) = (1+cos)/sin

How do you solve the problem?

Prove: 1/2(cotA-tanA) = cot2A

trig identitry

csc2(x) sec(x)=?

sin2Ø-1 = 1 ...

Provide an exact evaluation of the expression: tan (-285°).