If csc(α) = 3, where 0 < α < π/2, and β is a Quadrant II angle with tan(β) = −7, find cos(α+β) And there are others that I'm supposed to find, such as sin(α+β),...

If csc(α) = 3, where 0 < α < π/2, and β is a Quadrant II angle with tan(β) = −7, find cos(α+β) And there are others that I'm supposed to find, such as sin(α+β),...

Solve: 2sin2x=cotx , -π ≤ x ≤ 2π

find tan(A+B)

if cos theta = -2/6 and tan theta < 0, then what are all the other 5 trigonometric ratios tan(theta)= ? sin (theta) =? sec (theta) =? csc (theta) =? cot (theta) =?

I know how to solve these when it involves actual angles from the unit circle, but I can't seem to find it for those angles not on the unit circle.

sinΘ⁄ 1+cosΘ + 1+cosΘ/ sinΘ = 2cscΘ

1 + tanΘ / 1 + tanΘ = tanΘ

5tanx = 2sinsx solve for interval (0 2π) algebraic means without calculator

cos2x = cosx solve for interval (0 2π) algebraic means without calculator

5tanx = 2sin2x solve for interval (0 2π) algebraic means without calculator

sin4x - sin2x = 0 solve for interval (0 2π) algebraic means without calculator

sin x- sq root 3 cosx = 0 solve for interval (0 2π) algebraic means without calculator

sin (x/2) = 1- cosx solve for interval (0 2π) algebraic means without a calculator

(sinx+siny)/(cosx-cosy) = -cot(x-y/2) use left as given

sinxcosy = (1/2)(sin(x+y)+sin(x-y)) left side is the given

(1+cosx)/(sinx) + (sinx)/(1+cosx) = 2cscx use left side as given

Verify the Identity.

How do you solve the problem?

Proving a trig identity and I dont know what to do

I'm having trouble trying to prove this trig identity. Help is greatly appreciated. Thanks in advance. 1/(csc-cot) = (1+cos)/sin