Verify tan2x(1+cot2x)=sec2 x This is what I did: (tan2x)*(csc2)= (sin2 x/ cos2 x) * ( 1/sin2) = 1/cos2 =...

Verify tan2x(1+cot2x)=sec2 x This is what I did: (tan2x)*(csc2)= (sin2 x/ cos2 x) * ( 1/sin2) = 1/cos2 =...

The equation is tan(thetha)= 1/3 . [0,360)degrees How am I supposed to know how to find the angle? Is there some equation to do? I know the unit circle by heart so its what im using,...

a) 5Cos(thetha)=2 b) tan(thetha) +√3=0 Its asking to find exact solutions[0,360)degres. For a) , I dont know how to find 2/5 on the unit circle. I guess I am used to solving...

sin(thetha) -2sin(thetha)Cos(thetha) =0 There are 4 answers to this but I dont know why there are so many. I only found 2 .

2sin2 (thetha) = 1 When I solved , I got 2 of the answers right. But there are 4 answers. I got 45 and 135 degrees but the other two I have no idea how to find it. The other two...

tan(thetha) +√3=0 When I move the radical 3 to the rIght side, it becomes negative. I dont know how to solve when its negative. The question is asking...

cos(x)tan(x)csc(x)=1

Hi, I dont know what is meant by the question.

Find the values of tan(thetha) =3/4 and sin(thetha)<0 What I dont understand is the sin(thetha)<0

This question was asked on a practice test.

If a=4 b=7 and c=9 then A=???

Find the area of the following triangle a=43 inch b=53 inch c=72 inch

A hiker travel 7.5 hrs at 3.5 miles per hour at a heading of S 58° from a ranger station. A. How far is hiker from ranger station? B. How far east is the hiker from the...

A=15.6° b=10.25 c=5.5 a=?

If cos ∅=7/25 and Ø is in quadrant IV find CSC ∅ A. 25/7 B. 24/25 C. 25/24 D. -25/24 E. -24/25

Evaluate sec 127°

Find the area of the sector of the circle of the central angle ∅=320° and radius r=8.9 A. 1424.0 cm^2 B. 24.85 cm^2 C. 12673.6 cm^2 D. 221.20 cm^2 E. None

Convert the following from radians to degrees 3(3.14)/4

A central angle of 60° is inscribed in a circle with a radius of 7inch. What is the length of the intercepted arch? A. 8.5 inch B. 420 inch C. 7.33 inch D. .19 inch E. 7...

Please help this is urgent

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