this is for algebra 1 and I don't understand how to work it

this is for algebra 1 and I don't understand how to work it

I need to put the pair of points (-6,2) and (1,-8) into standard form, but i am struggling and I don't know how to do it

Write the standard form of the equation of the line through the given points

Write the standard form of the equation of the line through the given points

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How many passengers did the train carry in the year?Answer in standard form.

Line m passes through C(-2,0) and D(1,-3). Write the equation of line m in standard form.

8 + 3x = -9y

Write the equation of the line passing through the given points. Write the equation in standard form Ax+By=C. (-4,-2) and (-6,-1)

X=(3,5) passes through point -3,-36

Use the two points to write a slope-intercept equation. Then, transform it into Standard Form. (1,4) and (-5,-9)

Write Standard Form for a line with the points (1,4) and (3,9)

Write Standard-Form for a line with the slope of 5 and the point (2,5)

the answer choices I have are A. 3x-4y=12 B. 3x+4y=12 12x-4y=-3 12x+4y=-3

Write the standard form of the equation of the line through the given point with the slope through: (-2,5) , slope = -4 .

Ok so this question is telling me to write an equation in standard form for a line that passes through (2,2) and (0,-3)

Use the information given to write an equation in standard form

intercepts are (-7,0) and (3/5,0) what really got me is that fraction. THANKS!

I am just curious which one would be the preferable option when graphing a parabola

I am trying to rewrite x-9y=3 in standard form

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