I don't know the answer( honestly) I need help please. Thank you!

I don't know the answer( honestly) I need help please. Thank you!

Q. Solve using the quadratic formula: y = 3x² + 10x + 4 (-5 ± sqrt(22)) / 3 (10 ± i sqrt(38)) / 6 (-10 ± 13 sqrt(4)) / 6 (5 ± sqrt(12)) / 3 (-5 ± sqrt(13))...

solve the equation: the square root of x+2 - the square root of 2x+3 = -1

what are the solutions to the equation: the square root of x+5 + the square root of x-5 = 10

HELP!!!!!!!! I dont know where to start. solve for x

1) Can a negative be a perfect square? 2) Is -67 an integer? 3) Is 3/7 an integer? 4) What is the square root of 729 with a little 3 on the left of the square root sign? 5) What is...

Prove: SQUARE ROOT OF (3cosx+4sinx)2+(4cosx-3sinx)2 = 5 Please include step by step and the identities used next to each step! :)

It has rounding and it has decimals because it said round to the nearest tenth of an inch. It also has something to do with square root. Oh and it also has something to do with area.

Between which two consecutive whole numbers is square root of 30?

Write down a number that is greater than 17 and less than 18, and has a rational square root. (show and explain how you got this answer)

An expression is shown. 8√27 Which value is the best approximation for this expression?

According to the publication I've been using and an on-line function-graphing website, the graph of the function f(x)=the square root of (minus x) starts at the origin and extends up and asymtotically...

Sqaure root

(Hint: find the LCM)

Solve the equation by taking the square root: a2−45=0

^3√-1000x^3

Solve the equation 9 = square root of 27(4x + 6). Using complete sentences, explain the strategy used in solving this equation. Solve the equation 9 = square root of 27(4x + 6). Using...

We have to find x and then solve the second equasion.

(a) x2+1/x3 = y2 (b) lxl x3 = ³√y

I've already simplified this from -4 plus the square root of 32 over -2 times 5. I'm just a little confused on how to simplify it further, but I know it can be.