Write down a number that is greater than 17 and less than 18, and has a rational square root. (show and explain how you got this answer)
Write down a number that is greater than 17 and less than 18, and has a rational square root. (show and explain how you got this answer)
How do you round your or divide to get your decimal and then round it?
(Hint: find the LCM)
An expression is shown. 8√27 Which value is the best approximation for this expression?
1. The number of milligrams of a drug that remains in a patient's system after t hours is given by the function A(t) = Iert. Ted was given 200 milligrams of medicine which leaves his bloodstream at...
Sqaure root
Solve the equation by taking the square root: a2−45=0
^3√-1000x^3
How do you find the square root of any number?
^5√18
Solve the equation 9 = square root of 27(4x + 6). Using complete sentences, explain the strategy used in solving this equation. Solve the equation 9 = square root of 27(4x + 6). Using...
We have to find x and then solve the second equasion.
(a) x2+1/x3 = y2 (b) lxl x3 = ³√y
I've already simplified this from -4 plus the square root of 32 over -2 times 5. I'm just a little confused on how to simplify it further, but I know it can be.
Solve the equation 9 = square root of 27(4x + 6). Using complete sentences, explain the strategy used in solving this equation.
3 x square root of 27 = 3^n Find the value of n. Please explain how to answer this question. Thank you :) P.S. How do you insert a square root symbol (so as...
Describe the transformations applied to the parent function of f(x)=-3√ [2(x+4)] -1
I'm trying to do pythagorean theorem having a2 + b2 = 202. It has to be two different numbers.
According to the publication I've been using and an on-line function-graphing website, the graph of the function f(x)=the square root of (minus x) starts at the origin and extends up and asymtotically...
I cannot for the life of me figure this problem out and i cannot find an example like this in my math book. Please help! I need to know how to work this problem.