I had to turn the equation, y - 3 = 3(x + 1), into a perpendicular line that passes through (5,-1) and I got y= -1/3x + 2/3 which I think is correct. I just don't know how to turn it into...

I had to turn the equation, y - 3 = 3(x + 1), into a perpendicular line that passes through (5,-1) and I got y= -1/3x + 2/3 which I think is correct. I just don't know how to turn it into...

How would I turn the equation Y = 3x + -3 into standard form?

Write an equation in standard form of the line that passes through the given point, (-3,7) and has a slope of zero.

y+9=-5 (x-3) 9

Standard form

write the standard fourm of the equasion that is parallell to 2x-5y=-15and goes through (-5,4)

what is the slope for 4x-y=0

Given Points that it goes through: (1,2) Slope: 7 I am having a lot of trouble on this topic and I have an upcoming quiz on this topic. I am hoping to get my grades up. Please help...

Help So the formula you want to use is y = mx + b. b is the y intercept and m is the slope. Since the slope is 0: y=0x + b To find b substitute -4 for x and -2 for y: -2=0(-4)...

find the slope of 1/4x-3

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