The first "<" is a one with a line under it.

The first "<" is a one with a line under it.

sin(0)=(√0)/2 sin(π/6)=(√1)/2 sin(π/4)=(√2)/2 sin(π/3)=(√3)/2 sin(π/2)=(√4)/2 cos(0)=(√4)/2 cos(π/6)=(√3)/2 cos(π/4)=(√2)/2 cos(π/3)=(√1)/2 cos(π/2)=(√0)/2 Why...

exact answer i believe

I was messing with a calculator and found that the square root of 0.5 is equal to the sine and cosine of 45. I was just wondering the correlation between the two equations.

find all horizontal and vertical asymptotes of y=x/sinx vertical asymptotes: if i set denominator to 0, then sinx=0 and x= 0 or npi? horizontal asymptotes:...

Light passing through a double slit with separation d=3.33*10^-5 created its first minimum (m=1) at an angle of .551 deg. What is the wavelength of the light in nanometers? I thought...

Hello, I am having trouble with the following problem: If A and B are both acute angles and sin(A)=6/13 and cos(B)=48/49 find the value of cos9-A)-sin(-B). Write the answer as a simplified...

csc t = 3 and the terminal point of t is in Quadrant II.

Please help me answer the following question! I'm stuck! Prove that cos6ß + sin6ß = 1/4 + 3/4cos2ß I've tried simplifying out the LHS into (cos2ß)3 + (sin2ß)3,...

If the graph of y = sin(x) is shifted __?____ units left, the graph of y = cos(x) is obtained.

If sin(x) = 1/8 and x is in quadrant I, find the exact values of the expressions without solving for x. a) sin(2x) b) cos(2x) c) tan(2x)

Evaluate sin(sin-1(sin60)) [60 degrees] and evaluate cos-1(cos(cos-10.5)) if the angle is in quadrant 1.

Angle θ is an angle in standard position and B(-3,4) is a point on the terminal side of the angle. Find the value of sin(θ).

y=-5 sin(2x)

Background information: nsin(1/n) diverges using the Test for Divergence. I was playing around on my calculator and I noticed that no matter what term number you use the output...

trigonometry

As well as this one below. I'm just having trouble understanding the process and steps. Find all the solutions in [0,2pi) sin^2(t)-cos^2(t)=0 3. Solve...

I am modelling a graph in the form y = Asin(ωt +α) +c, but I have got stuck on calculating alpha. So far I have calculated... the central line is at y=100 A =...

sin 450°, cos(-780°), and tan (37π/6)

sin((pi)/(6))cos((pi)/(3)) - sin((pi)/(3))cos((PI)/(6))