No, because ƒ(c) = –4 Yes No, because ƒ(c) = 14 No, because ƒ(c) = –30

No, because ƒ(c) = –4 Yes No, because ƒ(c) = 14 No, because ƒ(c) = –30

Suppose that R(x) is a polynomial of degree 7 whose coefficients are real numbers. Also, suppose that R(x) has the following zeros. 4+i, -1+3i, -4i Answer...

f(x) = (x2 + 81)(x2 − 3x + 2)2 I believe I have the correct answers but the online site won't take them. I have x=1 multiplicity 2 ...

i need help with this problem canyou explain please

I HAVE ALREADY WORK ON IT FOR 2 HOURS AND i GOT NOTHING I EXPECT TO GET NO JUST AN ANSWER BUT ALSO A STEP BY STEP EXPLAINATION PLEASE THANK YOU SO MUCH

Use descartes rule of signs to determine the possible number of positive real zeros and the possible number of negative real zeros for the function: f(x)= 9x^7 + 3x^5 - 8x^3 + 7x - 1...

y= 4x^3 + 4x^2 - 7x +2 find all the real zeros. I dont know how to factor this fraction. I saw the Ac factoring thing but I didnt understand it. May someone explain to me please...

f(x)= x^4 - x^3 - 20x^2 Find all real zeros and determine the multiplicity of each. i did my factors and got 5,4,1,20,10,2 so i did synthetic with 5 and it was a factor. then I did synthetic...

Form a polynomial whose real zeros and degrees are given . give in factored form using a coefficient of 1. ZEROS:-3,0,2; degree:3