Hi, I keep getting 2a+2b but that's not the answer. I need some help solving the equation in the title. Thanks
-5√48 + 4√108
√14m5√7m5 So, what I was taught is to multiply through, so 14*7 and m5*m5 which would give me √98m10 I don't know where to go from there. &nb...
Hi, please help me understand solving this I'm a little lost : (√2x+4 -1) (√2x+4 -1) Note: The 4 is under the root but the 1 is not.
I am having problems with subtracting radicals. e.g 3√2-√2
3√ 2x+5 -15=0 (-15 is not under the radical)
How to work the problem it's a radical expression so "sqrt" is √ square root
7+ √3x = √5x+4 +5
Nina says that 16+4 (2) cannot be simplified. George says that is can be simplified to 20 (2). who is correct? Explain how you know. NOTE...
It's about subtracting radicals and then simplifying them.
Good evening, I am in need of assistance working through this problem. It is an example in my text book, so it lists out the steps. The problem is that I ended up at the second to last...
I'm very confused about how to separate the variables, and the numbers, or when to move stuff to the outside of the radical.
I know the answer is (3b^2c)/a but I don't know the steps.
Kepler's third law, T = √(Kr3), can be used to calculate the time it takes for a planet to complete one orbit of a star. The average radius of the planet's orbit in km is r, and K is a constant...
the question is √x+3 = √2x+8 I squared both ends to get x+3= 2x+8 I moved the variables to one side and the numbers...
A) (n-7)^2-25=0 B) (2r+3)^2=44
A) m^2-75=0 B) 3t^2=21