7+ √3x = √5x+4 +5
7+ √3x = √5x+4 +5
How to work the problem it's a radical expression so "sqrt" is √ square root
Nina says that 16+4 (2) cannot be simplified. George says that is can be simplified to 20 (2). who is correct? Explain how you know. NOTE...
It's about subtracting radicals and then simplifying them.
Good evening, I am in need of assistance working through this problem. It is an example in my text book, so it lists out the steps. The problem is that I ended up at the second to last...
simplify
I'm very confused about how to separate the variables, and the numbers, or when to move stuff to the outside of the radical.
I know the answer is (3b^2c)/a but I don't know the steps.
A) (n-7)^2-25=0 B) (2r+3)^2=44
A) m^2-75=0 B) 3t^2=21
the question is √x+3 = √2x+8 I squared both ends to get x+3= 2x+8 I moved the variables to one side and the numbers...
A). (5-√7)^2 B). (√2+3)^2
A). (12)-(24)(√14)/(16) B). (10x)-(√250x^3)/(2x)
A). (√6+1)(√6-) B). (4+root 3√3)(4-root3√3)
can someone do this with steps please?
Kepler's third law, T = √(Kr3), can be used to calculate the time it takes for a planet to complete one orbit of a star. The average radius of the planet's orbit in km is r, and K is a constant...
√6x + 7 =√7x+7 +6 Note only 6x is under radical on left side and 7x+7 are both under radical on right...
radical sign ----------------- | 180x75 ------ | --------- ...
The slashes that are between the numbers are supposed to be radical signs their not in my keyboard. And this is my problem and I forget how to do them. Please help!
learning operations with radicals. no logarithms please.