Solve using the quadratic formula, Round to the nearest tenth

Solve using the quadratic formula, Round to the nearest tenth

The height of a right-angled triangle is 3 cm more than the width. The area is 10 cm2. Find the width of the triangle.

the length of a rectangle exceeded twice its width by 3 inches. If the area is 10 square inches,.find the rectangle's dimensions. Round to the nearest tenth of an inch.

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Question1. 6x^2 – 36x + 42 = 0 Question2. 3x^2 – 48x + 153 = 0

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For each $6 decrease in price, the store expects to sell eight more calculators.The revenue from calculator sales is given by the function R(n) = (unit price)(units sold), or R(n) = (120 - 6n)(80...

Could someone help me with this question step-by-step using the quadratic formula? 3x² + 24x – 144

7x2 - 10x - 1 = 0

x2 - 2x + 9 = 0 A.)Find discriminant & determine types of solutions B.)Solve with with quadratic formula

I believe this question is very simple, I just would like to know why in this specific example (2x3+2x2-19x+20=0) once I am done plugging in the trinomial into the quadratic formula and get...

Use the quadratic formula to solve x^2 + 6x = 14. Show ALL work and Then describe the solution. Answer:

Use the quadratic formula to determine the exact solutions to the equation. 2x^2 − 5x + 1 = 0 Enter your answers in the boxes. x = ______ or x = ________

8n2 + 4n - 16 = -n2

The question is written like this: The width of a rectangle is (x+2) cm. The perimeter of the rectangle is 6(x+1) cm. The area of the rectangle is 18 cm2. Show that 2x2+5x-16=0...

Full Question: There are 3 squares. The first one is half the width of the second square. The second square is half the width of the third square. The total area is 1000 square feet. What is the combined...

What is the length and width?

i don't how to solve the question.can u please help me. i want the answer..

How do I know if this has One, Two, or No Real Solution? -3x^2 + 5x - 1 = 0

A newspaper's profit is $20 per year for each of its 2,500 subscribers. Management estimates that the profit per subscriber will increase by 1¢ for each additional subscriber over the current 2,500...