find the equation of the line that is perpendicular to 4y+x+40=O that passes through the point (1/2,0)

find the equation of the line that is perpendicular to 4y+x+40=O that passes through the point (1/2,0)

If the graph of the equation y=ax2+bx+c passes through the points (0,2), (-6,-7), and (8,-14), what's the value of a+b+c?

If y=ax^2+bx+c passes through the points (-3,10), (0,1), and (2,15), what's the value of a+b+c?

Scenario with formulas: Cost Function C(Q)= 8q+3200 Revenue Function R(Q)= -10p^2+850p ( in terms of q, (1/10q^2)+85q ...? I think?) Find the break...

Find the point on the line 5x+3y+1=0 which is closest to the point (–1,3). x= ? y=?

I have a rectangle of lined graph paper of 1mm squares. The rectangle is greater than 2r in height and width. Within the rectangle I randomly mark three or more points that are no further than 2r...

1) point (7,-6) and (9,4) are end points of the diameter of a circle. a) What is the length of the diameter? give the exact answer simplify as much as possible show work. b) What is the center...

Find the point on the graph of y=x2 +1 that is closest to the point (8, 3/2).

Consider the points (1,6) and (3,-2). (a.) State the midpoint of the line segment with the given endpoints. (b.) Find the distance between the points. Show some work. Give the exact answer...

Find the equation of a line through the points (-2,1) and (3,6)

I just need to understand how its done. I don't understand the midpoint formula.

need help with this equation

The answer I got is x= -2. Am i right?

find distance between each pair of points. (5,3) & (5,-3)

Write the equation of the line through the points: (-3,16) (12,4)

How to write an equation for the line in point-slope form and then re-write in slope-intercept form.

A line passes through the given points (-1,0),(1,2). Write an equation for the line in point-slope form. Then rewrite the equation in slope-intercept form.

y= x^2 y= 2^x y= (1/2)x y= |-3x| y= -|4x| y= 2x+ 3