Scenario with formulas: Cost Function C(Q)= 8q+3200 Revenue Function R(Q)= -10p^2+850p ( in terms of q, (1/10q^2)+85q ...? I think?) Find the break...
Scenario with formulas: Cost Function C(Q)= 8q+3200 Revenue Function R(Q)= -10p^2+850p ( in terms of q, (1/10q^2)+85q ...? I think?) Find the break...
Find the point on the line 5x+3y+1=0 which is closest to the point (–1,3). x= ? y=?
I just need to understand how its done. I don't understand the midpoint formula.
I have a rectangle of lined graph paper of 1mm squares. The rectangle is greater than 2r in height and width. Within the rectangle I randomly mark three or more points that are no further than 2r...
1) point (7,-6) and (9,4) are end points of the diameter of a circle. a) What is the length of the diameter? give the exact answer simplify as much as possible show work. b) What is the center...
Write the equation of the line through the points: (-3,16) (12,4)
Find the point on the graph of y=x2 +1 that is closest to the point (8, 3/2).
Consider the points (1,6) and (3,-2). (a.) State the midpoint of the line segment with the given endpoints. (b.) Find the distance between the points. Show some work. Give the exact answer...
Find the equation of a line through the points (-2,1) and (3,6)
The answer I got is x= -2. Am i right?
need help with this equation
find distance between each pair of points. (5,3) & (5,-3)
A line passes through the given points (-1,0),(1,2). Write an equation for the line in point-slope form. Then rewrite the equation in slope-intercept form.
y= x^2 y= 2^x y= (1/2)x y= |-3x| y= -|4x| y= 2x+ 3