Find a formula for the quadratic function whose graph has a vertex at (-7,-3) and contains the point (-3, -7)
Find a formula for the quadratic function whose graph has a vertex at (-7,-3) and contains the point (-3, -7)
I'm having trouble with the below question. I don't exactly understand how to answer the question. Suppose (3,-4) is on the graph of y=f(x). Use Theorem 1.7 to find a point on the graph...
The sets of points created by the midpoints of all chords of length 4 cm in a circle of radius 8 is a A)point B)line segment C)line D)semicircle E)circle I...
Which of the following is the equation of a line perpendicular to the line y=-3/2 x + 4 passing through the point (3,9) A.) 2x - 3y = 21 B.) -2x + 3y = 21 C.) 2x + 3y = 21 D...
The point (-3, -8) is reflected in the y-axis. What is the image of this point? The point (2, 4) is reflected in the line x = -3. What is the image of this point? The point (a, b) is reflected...
1) point (7,-6) and (9,4) are end points of the diameter of a circle. a) What is the length of the diameter? give the exact answer simplify as much as possible show work. b) What is the center...
Find the distance. P1=(3,-3);P2=(1,4)
7y=x+2 and 4x-8y=12 Thank you!!