Find the point on the line 5x+3y+1=0 which is closest to the point (–1,3). x= ? y=?
Find the point on the line 5x+3y+1=0 which is closest to the point (–1,3). x= ? y=?
I just need to understand how its done. I don't understand the midpoint formula.
write equation of parabola that has vertex (2,0) and goes through point (1,3) show work please
write equation of parabola that has vertex (-3,0) and goes through point (-5,4) please show work
Choose the point which is a solution to the system of inequalities: y <(line underneath)-x + 7 y < 3x + 11 Choose one answer. A. (5, 5) B...
Write the equation of the parabola in vertex form given the vertex: (1/4, -3/2) and point (1,3)
Find the point P where the line x = 1 + t, y = 2t, z = -3t intersects the plane x + y - z = -3.
Consider the two lines L1: x = -2t, y = 1 + 2t, z = 3t and L2: x = -9 + 5 s, y = 5 s, z = 2 + 4 s Find the point of intersection of the two lines....
Find the shortest distance from the point P= (7, 6, 4 ) to a point on the line given by l: (x,y,z)= (-7 t, 7 t, 1 t). the distance is:
Find the point on the line 4x+6y+1=0 which is closest to the point (-1,1)
I just don't understand at all. Could you maybe give me an example, then show your work and solve it?
A) no slope B) 0 C) 5/4