I have to find x! Can you help me lg= logarithm

I have to find x! Can you help me lg= logarithm

given that loga^2=0.693 , loga^6=1.792 , loga^5=1.609 find loga^60

15^9x=13^-x-7 write the exact answer using base -10 logarithm

e^2.4=11 write the equivalent logarithmic equation.

log x^(6/5)*y^(4/5) given that log x=2, log y =3. log 2 =0.3, and log 3=0.48 the answer is 24/5 but I dont know what to do after getting rid of the radical

So, in all, I'm really just asking how I would use log in general. (Please answer in a 'for dummies' format please! :) Not exactly the best with the vocabulary!) Due to some research, I've learned...

So there's this question. It's 1/2log(25)+log(4). Then we convert it to log(25^1/2) + log (4). But then the log converts to the square root of 25 from log(25^1/2). Why? And what does that...

Having trouble solving equation

I have to expand and simplify the logarithm log2(8x)

Its equivalent logarithmic form is logbx=y b = x = y =

logb(sqrt 128/3)

approximate logb 15b given that logb3≈2 and logb5≈5

Prove the quotient law of logarithms by applying algebraic reasoning.?

log(1-y) + log(4-y) = log(18-10y)

This an from a works sheet about logarithms and I am so confused.

The log base b of 5th root b squared is x

Log11m^7-33=-20

A company runs food service concessions for sporting events throughout the country. Their marketing research department chose a particular football stadium to test market a new jumbo hot dog. It was...

How are they not equal to one another. Please explain why. Thank you!

Its equivalent logarithmic form is b= x= y=

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