If log2sinx - log2cosx -log2(1-tan^2x) = -1, Then find x. Options : A) (nπ)/2 + π/8, n€Z B) nπ - π/8, n€Z C) (nπ)/4 + π/2, n€Z D) none of these Answer is...

If log2sinx - log2cosx -log2(1-tan^2x) = -1, Then find x. Options : A) (nπ)/2 + π/8, n€Z B) nπ - π/8, n€Z C) (nπ)/4 + π/2, n€Z D) none of these Answer is...

logx1 logx2...... logxn-1logxn (xnxn-1^xn-2^....x1)

Log5x+3log5x=2

Use logarithm properties to answer this question for me

How do i get rid of the e?

X=Log8(0.25) will it have same answer with Log8(0.25) without X?

solve x for the equation,log base 2 (5x^2-x-2)=2+2log base 2 x

Log2 (x-4) - log2 (2/x) = 5

1/3 [log4(x+3) log4 y-2 log4 z]

If you can afford to pay $900 per month, and you have $50,000 in debt in an interest-only loan which charges an annual interest rate of 9% (compounded monthly), it will take you 6 years to pay off...

Let logbA=3; logbC=2; logbD=5 What is the value of logbA5C2/D6 Answer Choices: -11, -15378, 2, or 49 I dont know how to do this..I have tried many times...

The value of x satisfying the equation 4^log10x+1-6log10x-(2)3log10x^2+2=0

if klog25=16, then the value of k(log25)^2= ??

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F(a) = log(1+a)/(1-a) then f(2a/(1+a2) = ?

A country's population doubled in 45 years. What is the exponential growth rate?Growth

7 ln x - 1/4 ln y I would be very grateful for some help! Thanks for reading!

I need help with graphing log base of 2 (4-X) I get confused with the shifting

I need to solve this equation: Log(3x+5) = 1 + (log (x-1)

I understand how to do this with e or ln but not a log

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