The half-life of radioactive (226Ra) is about 1599 years. That is, for a given amount of radium, half of the original amount will remain after 1599 years. After another 1599 years, one-quarter of...
Write as a single logarithm with coefficient 1
Find the answer using Logarithm
Solve 5^2x-1=20 Solve 9^5x=5^x+3
3logx+ 2log7- log y 1/2lnx-2/3lnx
If log2sinx - log2cosx -log2(1-tan^2x) = -1, Then find x. Options : A) (nπ)/2 + π/8, n€Z B) nπ - π/8, n€Z C) (nπ)/4 + π/2, n€Z D) none of these Answer is...
logx1 logx2...... logxn-1logxn (xnxn-1^xn-2^....x1)
X=Log8(0.25) will it have same answer with Log8(0.25) without X?
Use logarithm properties to answer this question for me
How do i get rid of the e?
Ln 3x/x+1 Log √x(x-1)/x^2
Log2 (x-4) - log2 (2/x) = 5
solve x for the equation,log base 2 (5x^2-x-2)=2+2log base 2 x
Let logbA=3; logbC=2; logbD=5 What is the value of logbA5C2/D6 Answer Choices: -11, -15378, 2, or 49 I dont know how to do this..I have tried many times...
if klog25=16, then the value of k(log25)^2= ??
1/3 [log4(x+3) log4 y-2 log4 z]
If you can afford to pay $900 per month, and you have $50,000 in debt in an interest-only loan which charges an annual interest rate of 9% (compounded monthly), it will take you 6 years to pay off...
The value of x satisfying the equation 4^log10x+1-6log10x-(2)3log10x^2+2=0
a= log2412 , b= log4836 , c= log3624 Then how to prove 1+abc = 2bc