lim(x-√(x^2+1)) as x goes to infinity

lim(x-√(x^2+1)) as x goes to infinity

lim (1+4x)^3/x as x goes to 0

Working on my calc bc homework and mildly stumped by this problem. I know that when graphed the answer is 3, but I need to get it into a form where I can use L'Hopital's rule and work it out.&nbs...

lim 1-cos(3x)/x^2 x→0 I took the derivative and got 3sin(3x)/2x, when I plug in zero I get 0/0 I took the derivative a second time and got 9cos(3x)/2, plugged in...

use L'Hopital rule to find limit.

limx=0(sinh(2x)) (cosh(3x)) find the limit using l'hopital's rule